複数の "OR"でMySQLクエリの部分一致を見つける

Question

MySQLクエリで部分一致または完全一致を見つける必要があります。私は 'OR'を使用して複数のテーブルでクエリを実行しており、すべての条件が満たされているかどうかを知る必要があります。

これを行う最も簡単な方法は、「部分的」という新しい列を作成することです（0または1のいずれかになります）。

ここ

は私のクエリです：

SELECT 
    id, confirmed, name, addressLine1, addressLine2, addressCity, addressPostcode, 
    addressLat, addressLon, 
    (6371 * acos(cos(radians('53.649779')) 
       * cos(radians(addressLat)) 
       * cos(radians(addressLon) - radians('-1.6026266')) 
       + sin(radians('53.649779')) * sin(radians(addressLat))) 
) distance 
FROM TABLE_NAME 
WHERE active = '1' 
    AND deleted = '0' 
    AND 
    (
    id < 0 
    OR 
    id IN 
    (
     SELECT establishmentID 
     FROM appEstablishmentDrinks 
     WHERE active = '1' 
     AND deleted = '0' 
     AND manufacturerDrinkID IN (101) 
     GROUP BY establishmentID 
     HAVING count(distinct manufacturerDrinkID) = 1 
    ) 
    OR 
    id IN 
    (
     SELECT establishmentID 
     FROM appEstablishmentFacilities 
     WHERE active = '1' 
     AND deleted = '0' 
     AND facilityID IN (37) 
    ) 
) 
HAVING distance < '15' 

Answer 1

のMySQLでは

true = 1とfalse = 0だから、単純に条件を追加します。(id < 0) + (id in (...)) + (id in (...))、あなたはすべての3試合以下を得たかどうかを確認してください。

SELECT 
    id, confirmed, name, addressLine1, addressLine2, addressCity, addressPostcode, 
    addressLat, addressLon, distance, 
    case when count_matches = 3 then 'full' else 'partial' end as matching 
FROM 
(
    SELECT 
    id, confirmed, name, addressLine1, addressLine2, addressCity, addressPostcode, 
    addressLat, addressLon, 
    (6371 * acos(cos(radians(53.649779)) 
       * cos(radians(addressLat)) 
       * cos(radians(addressLon) - radians(-1.6026266)) 
       + sin(radians(53.649779)) * sin(radians(addressLat))) 
    ) as distance, 
    (id < 0) 
    + 
    (
     id IN 
     (
     SELECT establishmentID 
     FROM appEstablishmentDrinks 
     WHERE active = 1 
      AND deleted = 0 
      AND manufacturerDrinkID IN (101) 
     GROUP BY establishmentID 
     HAVING count(distinct manufacturerDrinkID) = 1 
    ) 
    ) 
    + 
    (
     id IN 
     (
     SELECT establishmentID 
     FROM appEstablishmentFacilities 
     WHERE active = 1 
     AND deleted = 0 
     AND facilityID IN (37) 
    ) 
    ) as count_matches 
    FROM TABLE_NAME 
    WHERE active = 1 
    AND deleted = 0 
) x 
WHERE distance < 15 
AND count_matches > 0;