は、私は、このための解決策を見つけることができません

Question

をベースJSON配列の日付をマージ？ ：

解決策を見つけようとしていますが、わかりません。

[ 
    { 
    "date" : "2010-01-01", 
    "price" : 30 
    }, 
    { 
    "date" : "2010-02-01", 
    "price" : 40 
    }, 
    { 
    "date" : "2010-03-01", 
    "price" : 50 
    }, 
    { 
    "date" : "2010-01-01", 
    "price2" : 45 
    }, 
    { 
    "date" : "2010-05-01", 
    "price2" : 40 
    }, 
    { 
    "date" : "2010-10-01", 
    "price2" : 50 
    } 
] 

私はこれ欲しい：

[ 
    { 
     "date" : "2010-01-01", 
     "price" : 30, 
     "price2" : 45 
    }, 
    { 
     "date" : "2010-02-01", 
     "price" : 40, 
     "price2" : null 
    }, 
    { 
     "date" : "2010-03-01", 
     "price" : 50, 
     "price2" : null 
    }, 
    { 
     "date" : "2010-05-01", 
     "price" : null, 
     "price2" : 40 
    }, 
    { 
     "date" : "2010-10-01", 
     "price" : null 
     "price2" : 50 
    } 
] 

は、事前にありがとうございます。

Answer 1

最初にsort()メソッドを使用して日付で要素をソートし、次にforEach()を使用して要素を日付でグループ化することができます。あなたはをマージするループとObject.assignにArray.reduceとArray.mapを試すことができますArray.reduce()とArray.find()

var prices = [{"date":"2010-01-01","price":30},{"date":"2010-02-01","price":40},{"date":"2010-03-01","price":50},{"date":"2010-01-01","price2":45},{"date":"2010-05-01","price2":40},{"date":"2010-10-01","price2":50}]; 
 

 
var prices2 = prices.reduce(function(acc, val) { 
 
    var dateElement = acc.find(function(element) { 
 
    return val.date === element.date; 
 
    }); 
 

 
    if (!dateElement) { 
 
    dateElement = { 
 
     date: val.date, 
 
     price: null, 
 
     price2: null, 
 
    }; 
 
    acc.push(dateElement); 
 
    } 
 
    dateElement.price = dateElement.price || val.price; 
 
    dateElement.price2 = dateElement.price2 || val.price2; 
 

 
    return acc; 
 
}, []); 
 

 
console.log(prices2);

Answer 2

var data = [{"date":"2010-01-01","price":30},{"date":"2010-02-01","price":40},{"date":"2010-03-01","price":50},{"date":"2010-01-01","price2":45},{"date":"2010-05-01","price2":40},{"date":"2010-10-01","price2":50}] 
 

 
var result = data.reduce((p, c) => 
 
    (p[c.date] = Object.assign({},{price: null, price2:null}, p[c.date], c)) && p 
 
    , {}); 
 

 
var final = Object.keys(result).map(x=>result[x]) 
 

 
console.log(final)

Answer 3

を使用して

var data = [{"date":"2010-01-01","price":30},{"date":"2010-02-01","price":40},{"date":"2010-03-01","price":50},{"date":"2010-01-01","price2":45},{"date":"2010-05-01","price2":40},{"date":"2010-10-01","price2":50}] 
 
data.sort((a, b) => new Date(a.date) - new Date(b.date)) 
 

 
var result = [] 
 
data.forEach(function(e) { 
 
    if(!this[e.date]) { 
 
    this[e.date] = {date: e.date, price: null, price2: null} 
 
    result.push(this[e.date]) 
 
    } 
 
    this[e.date] = Object.assign(this[e.date], e) 
 
}) 
 

 
console.log(JSON.stringify(result, 0, 4))

Answer 4

あなたが同じ日を基準としてオブジェクトを使用することができます。

var data = [{ date: "2010-01-01", price: 30 }, { date: "2010-02-01", price: 40 }, { date: "2010-03-01", price: 50 }, { date: "2010-01-01", price2: 45 }, { date: "2010-05-01", price2: 40 }, { date: "2010-10-01", price2: 50 }], 
 
    grouped = []; 
 

 
data.forEach(function (hash) { 
 
    return function (o) { 
 
     if (!hash[o.date]) { 
 
      hash[o.date] = { date: o.date, price: null, price2: null }; 
 
      grouped.push(hash[o.date]); 
 
     } 
 
     Object.keys(o).forEach(function (k) { 
 
      if (k === 'date') { 
 
       return; 
 
      } 
 
      hash[o.date][k] = o[k]; 
 
     }); 
 
    }; 
 
}(Object.create(null))); 
 

 
console.log(grouped);

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