今日、昨日、1日前、2日前のデータは？

Question

$active_count1_end=date('Y-m-d'); 
$active_count1_end.=" 23:59:59"; 
$active_count1_start=date('Y-m-d'); 
$active_count1_start.=" 00:00:00"; 
$count10=$today->query("select count(*) as count1 from talk where time1 between '". $active_count1_start."' and '".$active_count1_end."'"); 
$count11=$today->query("select count(*) as count2 from reply where time2 between '". $active_count1_start."' and '".$active_count1_end."'"); 
$count1=$count10[0][count1]+$count11[0][count2]; 

$active_count2_end=strtotime($active_count1_end)-24*3600; 
$active_count2_end=date('Y-m-d',$active_count2_end); 
$active_count2_end.=" 23:59:59"; 
$active_count2_start=strtotime($active_count1_end)-24*3600; 
$active_count2_start=date('Y-m-d',$active_count2_start); 
$active_count2_start.=" 00:00:00"; 
$count20=$today->query("select count(*) as count1 from talk where time1 between '". $active_count2_start."' and '".$active_count2_end."'"); 
$count21=$today->query("select count(*) as count2 from reply where time2 between '". $active_count2_start."' and '".$active_count2_end."'"); 
$count2=$count20[0][count1]+$count21[0][count2]; 

$active_count3_end=strtotime($active_count2_end)-24*3600; 
$active_count3_end=date('Y-m-d',$active_count3_end); 
$active_count3_end.=" 23:59:59"; 
$active_count3_start=strtotime($active_count2_end)-24*3600; 
$active_count3_start=date('Y-m-d',$active_count3_start); 
$active_count3_start.=" 00:00:00"; 
$count30=$today->query("select count(*) as count1 from talk where time1 between '". $active_count3_start."' and '".$active_count3_end."'"); 
$count31=$today->query("select count(*) as count2 from reply where time2 between '". $active_count3_start."' and '".$active_count3_end."'"); 
$count3=$count30[0][count1]+$count31[0][count2]; 

$active_count4_end=strtotime($active_count3_end)-24*3600; 
$active_count4_end=date('Y-m-d',$active_count4_end); 
$active_count4_end.=" 23:59:59"; 
$active_count4_start=strtotime($active_count3_end)-24*3600; 
$active_count4_start=date('Y-m-d',$active_count4_start); 
$active_count4_start.=" 00:00:00"; 
$count40=$today->query("select count(*) as count1 from talk where time1 between '". $active_count4_start."' and '".$active_count4_end."'"); 
$count41=$today->query("select count(*) as count2 from reply where time2 between '". $active_count4_start."' and '".$active_count4_end."'"); 
$count4=$count40[0][count1]+$count41[0][count2]; 

コードがフォーラムを作るために使用されるへのアクセスを容易にするための方法、 $count1は、今日のデータ、 $count2は昨日のデータ、 $count3です。 ..、 $count4 ... もちろん、コードにはエラーはありませんが、うまく見えません。 コードの最適化メソッドがありますか？

Answer 1

この記事をよくお読みください。

http://www.php.net/manual/en/datetime.formats.relative.php