Django Feed error： 'function'オブジェクトに 'startswith'という属性がありません。

Question

Django 1.8で作業していて、プロジェクト用の簡単なフィードを作成しようとしています。ここでは、フィードを作成するfeeds.pyファイルは次のとおりです。

from django.contrib.syndication.views import Feed 
from django.template.defaultfilters import truncatewords 
from valueFact.models import ValueFactPost 


class LatestPostsFeed(Feed): 
    title = "Contributions from members" 
    link = "/companies/" 
    description = "New Contributions by members" 

    def items(self): 
     return ValueFactPost.published.all()[:5] 

    def item_title(self, item): 
     return item.title 

    def item_description(self, item): 
     return truncatewords(item.body, 30) 

マイアプリのurl.pyファイルは、次のとおりです。私は、URL「企業/フィード」にブラウザに指示

from django.conf.urls import url 

from valueFact import views 
from valueFact.feeds import LatestPostsFeed 


urlpatterns = [ 
    url(r'^$', 
     views.valueFactListView.as_view(), 
     name='valueFact_list'), 
    url(r'^(?P<year>\d{4})/(?P<post>[-\w]+)/$', 
     views.valuefact_detail, 
     name='valuefact_detail'), 
    url(r'^(?P<fact_id>\d+)/share/$', 
     views.valuefact_share, 
     name='valuefact_share'), 
    url(r'^feed/$', LatestPostsFeed(), name='post_feed'), 
] 

、および次のエラーが発生します。私は既にこのプロジェクトのすべてのURLをメインプロジェクトのurl confファイルに含めてあり、正常に動作していることに注意してください（例えば、127.0.0.1:8000/companiesと入力したときに必要なページが表示されます）

編集：完全なトレースです

Environment:

Request Method: GET Request URL: http://127.0.0.1:8000/companies/feed/

Django Version: 1.8 Python Version: 3.5.0 Installed Applications: ('django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.messages', 'django.contrib.staticfiles', 'django.contrib.admin', 'django.contrib.sites', 'django.contrib.sitemaps', 'djangobower', 'rest_framework', 'stockData', 'accounts', 'functional_tests', 'valueFact') Installed Middleware: ('django.contrib.sessions.middleware.SessionMiddleware', 'django.middleware.common.CommonMiddleware', 'django.middleware.csrf.CsrfViewMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'django.contrib.auth.middleware.SessionAuthenticationMiddleware', 'django.contrib.messages.middleware.MessageMiddleware', 'django.middleware.clickjacking.XFrameOptionsMiddleware', 'django.middleware.security.SecurityMiddleware')

Traceback: File "/Users/djunh/Programming/viex/virtualenv/lib/python3.5/site-packages/django/core/handlers/base.py" in get_response 132. response = wrapped_callback(request, *callback_args, **callback_kwargs) File "/Users/djunh/Programming/viex/virtualenv/lib/python3.5/site-packages/django/contrib/syndication/views.py" in call 43. feedgen = self.get_feed(obj, request) File "/Users/djunh/Programming/viex/virtualenv/lib/python3.5/site-packages/django/contrib/syndication/views.py" in get_feed 174. request.is_secure(), File "/Users/djunh/Programming/viex/virtualenv/lib/python3.5/site-packages/django/contrib/syndication/views.py" in add_domain 19. if url.startswith('//'):

Exception Type: AttributeError at /companies/feed/ Exception Value: 'function' object has no attribute 'startswith'

ありがとうございます！

Answer 1

あなたのモデルにget_absolute_url(self)を定義しない場合は、docsからitem_link

# item_link is only needed if NewsItem has no get_absolute_url method. 
def item_link(self, item): 
    return reverse('news-item', args=[item.pk]) 

を定義する必要があるかもしれません：

To specify the contents of <link> , you have two options. For each item in items(), Django first tries calling the item_link() method on the Feed class. In a similar way to the title and description, it is passed it a single parameter, item. If that method doesn’t exist, Django tries executing a get_absolute_url() method on that object. Both get_absolute_url() and item_link() should return the item’s URL as a normal Python string. As with get_absolute_url(), the result of item_link() will be included directly in the URL, so you are responsible for doing all necessary URL quoting and conversion to ASCII inside the method itself.