依存サブクエリから自己結合

Question

次の従属サブクエリを自己結合に変更するにはどうすればよいですか？

SELECT d.name, d.created, 
(SELECT SUM(q1.payout) FROM client AS q1 WHERE q1.uid = d.uid) AS payout, 
(SELECT COUNT(q2.uid) FROM client AS q2 WHERE q2.uid = d.uid AND q2.winning =1) AS cnt 
FROM client AS d group by d.name, d.created ORDER BY cnt DESC LIMIT 0 , 10; 

Answer 1

SELECT d.name, d.created, SUM(q1.payout) AS psum, COUNT(q2.uid) AS cnt 
FROM client d 
LEFT JOIN 
     client q1 
ON  q1.uid = d.uid 
LEFT JOIN 
     client q2 
ON  q2.uid = d.uid 
     AND q2.winning =1 
GROUP BY 
     d.name, d.created 
ORDER BY 
     cnt DESC 
LIMIT 0, 10 

uidがPRIMARY KEYであれば、あなたはこのようにそれを書き換えることができます。

SELECT d.name, d.created, SUM(payout) AS psum, COUNT(IF(winning = 1, uid, NULL)) AS cnt 
FROM client d 
GROUP BY 
     d.name, d.created 
ORDER BY 
     cnt DESC 
LIMIT 0, 10 

Answer 2

SELECT d.name, d.created, SUM(d.payout) AS allpayout, COUNT(alt.uid) as cnt 
FROM client AS d 
LEFT JOIN client AS alt 
ON alt.uid = d.uid AND alt.winning = 1 
GROUP BY d.name, d.created 
ORDER BY cnt DESC 
LIMIT 0, 10 

Answer 3

SELECT d.name, d.created, SUM(d.payout) AS payout, SUM(IF(d.winning = 1, 1, 0)) AS cnt 
FROM client AS d 
GROUP BY 
    d.name, d.created 
ORDER BY cnt DESC LIMIT 0 , 10;