クエリSQLの列に

Question

私はこれがあります。

Num Store  Credit No_credit 
1  Store 1 10   20 
2  Store 3 50   80 

このことが可能です：

Id  Store  Situation Total 
1  Store 1  Credit  10 
2  Store 1  No credit 20 
3  Store 3  Credit  50 
4  Store 3  No credit 80 

を私はこれがしたいですか？

ありがとうございました。

Answer 1

これはちょうど、条件付きの集約です：

select store, 
     sum(case when situation = 'Credit' then total else 0 end) as Credit, 
     sum(case when situation = 'No Credit' then total else 0 end) as NoCredit, 
from t 
group by store; 

あなたはまたidを追加することができます。

select row_number() over (order by store) as id, 
     store, 
     sum(case when situation = 'Credit' then total else 0 end) as Credit, 
     sum(case when situation = 'No Credit' then total else 0 end) as NoCredit, 
from t 
group by store 
order by store;