foreach関数はデータベースの値が正しく表示されません

Question

ここにはそれぞれのコードがあります。あなたの値を取得

<?php 
     foreach($result as $query2) 

        echo '<tr>'; 
     echo "<td>" . $query2['firstname']. "</td>"; 
     echo"<td>".$query2['username']."</td>"; 
     echo"<td>".$query2['firstname']."</td>"; 
     echo"<td>".$query2['lastname']."</td>"; 
     echo"<td>".$query2['gender']."</td>"; 
     echo"<td>".$query2['email']."</td>"; 
     echo"<td>".$query2['mobile']."</td>"; 
     echo"<td>".$query2['address']."</td>"; 
     echo "<td><a href='http://localhost/service/change.php?edit_id=".$query2['uid']."'>Edit</a></td>"; 
     //echo"<td><a href="http://localhost/service/change.php?edit_id= ".$query2['uid']."">Edit</a> 
     //<a href="http://localhost/service/delete.php?delet_id=<?php echo $query2['uid']?X</a></td> 
        echo "<td><a href='http://localhost/service/delete.php?delet_id=".$query2['uid']."'>x</a></td>"; 
      echo '</tr>'; 


     ?> 

Answer 1

使用そのためのキー - 値参照....

foreach($result as $key=>$value) 
{ 
    echo "<td>" . $value['firstname']. "</td>"; 
    echo "<td>" . $value['lastname']. "</td>"; 
}