一般に、私はコード内のデータを隠すのは良い考えではないと思います。データがテーブルに属します:
SET search_path='tmp';
-- create some data
DROP TABLE tmp.student CASCADE;
CREATE TABLE tmp.student
(sno INTEGER NOT NULL
, grade INTEGER
, sname varchar
);
INSERT INTO tmp.student(sno) SELECT generate_series(1,10);
UPDATE tmp.student SET grade = sno*sno;
DROP TABLE tmp.entry CASCADE;
CREATE TABLE tmp.entry
(sno INTEGER NOT NULL
, sdate TIMESTAMP
);
INSERT INTO tmp.entry(sno) SELECT generate_series(1,10);
-- table with interval lookup
DROP TABLE tmp.lookup CASCADE;
CREATE TABLE tmp.lookup
(llimit NUMERIC NOT NULL
, hlimit NUMERIC
, result varchar
);
INSERT INTO lookup (llimit,hlimit,result) VALUES(70, NULL, 'Excellent'), (50, 70, 'Passed'), (30, 50, 'Failed')
;
CREATE OR REPLACE FUNCTION stud_result(integer,numeric) RETURNS text
AS $BODY$
DECLARE
stunum ALIAS FOR $1;
grade ALIAS FOR $2;
result TEXT;
BEGIN
SELECT COALESCE(lut.result, 'NOT TAKEN') INTO result
FROM student st, entry en
LEFT JOIN lookup lut ON (grade >= lut.llimit
AND (grade < lut.hlimit OR lut.hlimit IS NULL))
WHERE st.sno = en.sno
AND st.sno = stunum
;
RETURN result;
END; $BODY$ LANGUAGE PLPGSQL;
-- query joining students with their function values
SELECT st.*
, stud_result (st.sno, st.grade)
FROM student st
;
しかし、待って:あなただけのようにも醜い機能せずに行うことができます。
-- Plain query
SELECT
st.sno, st.sname, st.grade
, COALESCE(lut.result, 'NOT TAKEN') AS result
FROM student st
LEFT JOIN lookup lut ON (1=1
AND lut.llimit <= st.grade
AND (lut.hlimit > st.grade OR lut.hlimit IS NULL)
)
JOIN entry en ON st.sno = en.sno
;
結果:
sno | grade | sname | stud_result
-----+-------+-------+-------------
1 | 1 | | NOT TAKEN
2 | 4 | | NOT TAKEN
3 | 9 | | NOT TAKEN
4 | 16 | | NOT TAKEN
5 | 25 | | NOT TAKEN
6 | 36 | | Failed
7 | 49 | | Failed
8 | 64 | | Passed
9 | 81 | | Excellent
10 | 100 | | Excellent
(10 rows)
sno | sname | grade | result
-----+-------+-------+-----------
1 | | 1 | NOT TAKEN
2 | | 4 | NOT TAKEN
3 | | 9 | NOT TAKEN
4 | | 16 | NOT TAKEN
5 | | 25 | NOT TAKEN
6 | | 36 | Failed
7 | | 49 | Failed
8 | | 64 | Passed
9 | | 81 | Excellent
10 | | 100 | Excellent
(10 rows)
私があなただったら、最初のtヒンジを試してみると、より小さな*機能になります。何もしないものを作ってください。次に、(a)関数を作成する際の問題か、(b)作成した関数の問題かどうかを確認できます。 –