PHPのISSET機能

Question

if($line_of_text['EMPDesignation3'] == ''^$line_of_text['EmpName3'] == '') { 
         $error_status['success_msg'] = "emp designation3 and emp name3 not empty"; 
         $error_status['status'] = 0; 
         return $error_status; 
        } 

はエラー通知示す：不定ランキング：

Answer 1

でEMPDesignation3は、XOR演算子でISSETためのコードの下に試し：

if(isset($line_of_text['EMPDesignation3'])^isset($line_of_text['EmpName3'])) { 
    $error_status['success_msg'] = "emp designation3 and emp name3 not empty"; 
    $error_status['status'] = 0; 
    return $error_status; 
    }