次のコードを2D配列にするにはどうすればよいですか？また

Question

、私はそれは、接続4ボードのように見えるので、sが全て消えている」角括弧のすべてのようにそれを作るとどうすればよいですか？

Row7 = [" ","A","B","C","D","E","F","G"] 
Row6 = ["1","-","-","-","-","-","-","-"] 
Row5 = ["2","-","-","-","-","-","-","-"] 
Row4 = ["3","-","-","-","-","-","-","-"] 
Row3 = ["4","-","-","-","-","-","-","-"] 
Row2 = ["5","-","-","-","-","-","-","-"] 
Row1 = ["6","-","-","-","-","-","-","-"] 

board = [[Row7], [Row6], [Row5], [Row4], [Row3], [Row2], [Row1]] 

print (board) 

だから、可能であれば、私はそれはのようになりたいですこれ：

ABCDEFG

1 - - - - - - -

2 - - - - - - -

3 - - - - - - -

4 - - - - - - -

5 - - - - - - -

6 - - - - - - -

それはあまりにも2D配列である必要があります！ 何か助けていただければ幸いです。

Answer 1

あなたはただあなたがこれまでにしようとしているものを私たちに伝えるために必要な2次元配列（リストのリスト）として

board = [[" ","A","B","C","D","E","F","G"], 
     ["1","-","-","-","-","-","-","-"], 
     ["2","-","-","-","-","-","-","-"], 
     ["3","-","-","-","-","-","-","-"], 
     ["4","-","-","-","-","-","-","-"], 
     ["5","-","-","-","-","-","-","-"], 
     ["6","-","-","-","-","-","-","-"]] 
#or if you need the rows 
# Row7 is an list... so board will be a list of lists (2d array) 
# board = [Row7, Row6, Row5, Row4, Row3, Row2, Row1] 

def printB(board) : 
    for row in board: 
     print(" ".join(row)) 


printB(board) 


> A B C D E F G 
1 - - - - - - - 
2 - - - - - - - 
3 - - - - - - - 
4 - - - - - - - 
5 - - - - - - - 
6 - - - - - - -