PHPを使用してSQLテーブルをソートする

Question

PHPを使用してテーブルをソートする際に問題があります。私は、コードを損なうことなく、基準でテーブルをソートできるボタンを作成する方法を理解したいだけです。基準は、3つの列「Price」、「ArtistName」、および「AlbumName」を昇順および降順にソートすることです。私は意見を楽しみにしており、私は任意のヒントに感謝します。

<?php 
$con = mysqli_connect("", "", "", ""); 
if (!$con) { 
die("Error: " . mysqli_connect_error()); 
} 
$mysqlget = "SELECT * FROM Albums"; 
$mysqldata = mysqli_query($con, $mysqlget) or die ("Error: " . mysql_error($con)); 

echo "<table class='table_albums'>"; 
echo "<tr><th>Album</th><th>Description</th><th>Artist</th><th>Price</th><th colspan='2'>Additional Options</th></tr>"; 

while ($row = mysqli_fetch_array($mysqldata, MYSQLI_ASSOC)) { 

echo "<tr><td>"; 
echo "<img class='album_artwork' src='"; 
echo $row['AlbumImage']; 
echo "'></td><td><p class='info_album_artist'>"; 
echo $row['Info']; 
echo "<p></td><td>"; 
echo "<img class='artist_artwork' src='"; 
echo $row['ArtistImage']; 
echo "'></td><td><p class='info_album_artist'>&pound;"; 
echo $row['Price']; 
echo "<p></td><td>"; 
echo "<a href='"; 
echo $row['MoreInfo']; 
echo "' class='more_info'>More Info</a></td><td>"; 
echo $row['Buy']; 
echo "</td></tr>"; 

} 

echo "</table>"; 
?> 

Answer 1

があり、あなたは、クエリで並べ替えることができるすべてのオプション

<form method="post" action=""> 
<select name="sort" onchange="this.form.submit()"> 
    <option>Order by ...</option> 
    <option value="price_desc">Price descending</option> 
    <option value="price_asc">Price ascending</option> 
    <option value="artist_name_desc">Artist Name descending</option> 
    <option value="artist_name_asc">Artist Name ascending</option> 
    <option value="album_name_desc">Album Name descending</option> 
    <option value="album_name_asc">Album Name ascending</option> 
</select> 
</form> 

<?php 

$sort = $_POST['sort']; 

if ($sort == 'price_desc') 
{ 
    $mysqlget = "SELECT * FROM Albums ORDER BY Price DESC"; 
} 
else if ($sort == 'price_asc') 
{ 
    $mysqlget = "SELECT * FROM Albums ORDER BY Price ASC"; 
} 
else if ($sort == 'artist_name_desc') 
{ 
    $mysqlget = "SELECT * FROM Albums ORDER BY ArtistName DESC"; 
} 
else if ($sort == 'artist_name_asc') 
{ 
    $mysqlget = "SELECT * FROM Albums ORDER BY ArtistName ASC"; 
} 
else if ($sort == 'album_name_desc') 
{ 
    $mysqlget = "SELECT * FROM Albums ORDER BY AlbumName DESC"; 
} 
else if ($sort == 'album_name_asc') 
{ 
    $mysqlget = "SELECT * FROM Albums ORDER BY AlbumName ASC"; 
} 
else 
{ 
    $mysqlget = "SELECT * FROM Albums"; 
} 

$mysqldata = mysqli_query($con, $mysqlget) or die ("Error: " . mysql_error($con)); 

echo "<table class='table_albums'>"; 
echo "<tr><th>Album</th><th>Description</th><th>Artist</th><th>Price</th><th colspan='2'>Additional Options</th></tr>"; 

while ($row = mysqli_fetch_array($mysqldata, MYSQLI_ASSOC)) { 

echo "<tr><td>"; 
echo "<img class='album_artwork' src='"; 
echo $row['AlbumImage']; 
echo "'></td><td><p class='info_album_artist'>"; 
echo $row['Info']; 
echo "<p></td><td>"; 
echo "<img class='artist_artwork' src='"; 
echo $row['ArtistImage']; 
echo "'></td><td><p class='info_album_artist'>&pound;"; 
echo $row['Price']; 
echo "<p></td><td>"; 
echo "<a href='"; 
echo $row['MoreInfo']; 
echo "' class='more_info'>More Info</a></td><td>"; 
echo $row['Buy']; 
echo "</td></tr>"; 

} 

echo "</table>"; 

?> 

Answer 2

これはSQLを使用すると簡単です。例：情報による

並べ替え：降順で

SELECT * FROM Albums ORDER BY Info 

並べ替え：

SELECT * FROM Albums ORDER BY Info DESC 

---

テーブルを並べ替えるボタンを作るために、私はGET使用する、のような：

<a href="?orderby=Info">Info</a> 

PHPコード：

$mysqlget = 'SElECT * FROM Albums'; 

if (isset($_GET['orderby'])) { 
    switch ($_GET['orderby']) { 
     case 'Info': 
      $mysqlget .= ' ORDER BY Info'; 
      break; 
     case 'Artist': 
      $mysqlget .= ' ORDER BY Artist'; 
      break; 
     // ... 
    } 
} 

$mysqldata = mysqli_query($con, $mysqlget) or die ("Error: " . mysql_error($con));