LodashまたはJS GROUPBYと私が入力してい配列

Question

のアレイの数：

results = [ 
    [ "Mon Nov 14 08:08:14 GMT+07:00 2016", "Ian Warner", "ian.warner@drykiss.com", "DryKISS1", "small", "SW192EZ", "undefined" ], 
    [ "Mon Nov 14 08:08:14 GMT+07:00 2016", "Ian Warner", "ian.warner@drykiss.com", "DryKISS2", "large", "SW192EZ", "undefined" ], 
    [ "Mon Nov 14 08:08:14 GMT+07:00 2016", "Ian Warner", "ian.warner@drykiss.com", "DryKISS2", "large", "SW192EZ", "undefined" ], 
    [ "Mon Nov 14 08:08:14 GMT+07:00 2016", "Ian Warner", "ian.warner@drykiss.com", "DryKISS2", "medium", "SW192EZ", "undefined" ], 
] 

を私は出力が

small 
    DryKISS1 : 1 
medium 
    DryKISS2 : 1 
large 
    DryKISS1 : 5 
    DryKISS2 : 2 
    DryKISS3 : 1 

は、基本的にはサイズによってグループ化して、会社名を合計するような何かになりたいです同じサイズの括弧で囲みます。

私は以下で遊んでてきたが、ほとんどの例として迷子に任意のヘルプは、プレーンJavaScriptで

Answer 1

を高く評価し、ハッシュ/オブジェクト

console.log _.chain(results).groupBy(4).map((value, key) -> 
    [ 
    key 
    _.reduce(value, ((result, currentObject) -> 
     { 
     company: result[ 3 ] 
     } 
    )) 
    ] 
).value() 

ためのもので、ネストされたとのオブジェクトを使用することができますカウントのプロパティ。最大で

var results = [["Mon Nov 14 08:08:14 GMT+07:00 2016", "Ian Warner", "ian.warner@drykiss.com", "DryKISS1", "small", "SW192EZ", "undefined"], ["Mon Nov 14 08:08:14 GMT+07:00 2016", "Ian Warner", "ian.warner@drykiss.com", "DryKISS2", "large", "SW192EZ", "undefined"], ["Mon Nov 14 08:08:14 GMT+07:00 2016", "Ian Warner", "ian.warner@drykiss.com", "DryKISS2", "large", "SW192EZ", "undefined"], ["Mon Nov 14 08:08:14 GMT+07:00 2016", "Ian Warner", "ian.warner@drykiss.com", "DryKISS2", "medium", "SW192EZ", "undefined"]], 
 
    grouped = {}; 
 

 
results.forEach(function (a) { 
 
    grouped[a[4]] = grouped[a[4]] || {}; 
 
    grouped[a[4]][a[3]] = (grouped[a[4]][a[3]] || 0) + 1; 
 
}); 
 

 
console.log(grouped);

その後、3列でアイテムをカウントする変換使用し、4列目で

var results = [["Mon Nov 14 08:08:14 GMT+07:00 2016", "Ian Warner", "ian.warner@drykiss.com", "DryKISS1", "small", "SW192EZ", "undefined"], ["Mon Nov 14 08:08:14 GMT+07:00 2016", "Ian Warner", "ian.warner@drykiss.com", "DryKISS2", "large", "SW192EZ", "undefined"], ["Mon Nov 14 08:08:14 GMT+07:00 2016", "Ian Warner", "ian.warner@drykiss.com", "DryKISS2", "large", "SW192EZ", "undefined"], ["Mon Nov 14 08:08:14 GMT+07:00 2016", "Ian Warner", "ian.warner@drykiss.com", "DryKISS2", "medium", "SW192EZ", "undefined"]], 
 
    grouped = {}, 
 
    max = { count: 0, keys: [] }; 
 

 
results.forEach(function (a) { 
 
    grouped[a[4]] = grouped[a[4]] || {}; 
 
    grouped[a[4]][a[3]] = (grouped[a[4]][a[3]] || 0) + 1; 
 
    if (grouped[a[4]][a[3]] > max.count) { 
 
     max = { count: grouped[a[4]][a[3]], keys: [{ size: a[4], group: a[3] }] }; 
 
     return; 
 
    } 
 
    if (grouped[a[4]][a[3]] === max.count) { 
 
     max.keys.push = { size: a[4], group: a[3] }; 
 
    } 
 
}); 
 

 
console.log(max); 
 
console.log(grouped);

.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 2

グループを数える：

var data = [ 
 
    ["Mon Nov 14 08:08:14 GMT+07:00 2016", "Ian Warner", "ian.warner@drykiss.com", "DryKISS1", "small", "SW192EZ", "undefined"], 
 
    ["Mon Nov 14 08:08:14 GMT+07:00 2016", "Ian Warner", "ian.warner@drykiss.com", "DryKISS2", "large", "SW192EZ", "undefined"], 
 
    ["Mon Nov 14 08:08:14 GMT+07:00 2016", "Ian Warner", "ian.warner@drykiss.com", "DryKISS2", "large", "SW192EZ", "undefined"], 
 
    ["Mon Nov 14 08:08:14 GMT+07:00 2016", "Ian Warner", "ian.warner@drykiss.com", "DryKISS2", "medium", "SW192EZ", "undefined"], 
 
]; 
 
    
 
var result = _(data) 
 
    .groupBy(4) 
 
    .transform(function(result, items, key) { 
 
    result[key] = _.countBy(items, 3); 
 
    }) 
 
    .value(); 
 
    
 
console.log(result);

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