SQL Server 2012でグループ内の値が異なる場合の合計値

Question

ManagerのB_Allocation値が異なる場合、別の値を合計する必要があります。たとえばManager 5の場合、10800、661782.60、2141987.20、および2163743.43を合計できるようにしたいと考えています。彼らは（Original Image）以下で表示されるそのB_Allocation明瞭ではありません6、8、14のような管理職のために、私は値が欲しい

select 
      BU.BuCode 
     , PE.ManagerID 
     , BUA.AllocatedAmount as B_Allocation 
     , PE.AllocatedAmount 
    from CFMS_ProjectEntry PE 
    join CFMS_BUAllocation BUA on BUA.BUDGETENTRYID = PE.BUDGETENTRYID 
    join CFMS_BU   BU on BU.BUID   = BUA.BUID 
    join CFMS_User   US on US.UserID   = PE.ManagerID 
    where BUCODE = 42406016 
    group by BU.BUCode 
      , ManagerID 
      , BUA.AllocatedAmount 
      , PE.AllocatedAmount 

私は（Original Image）欲しい：

+ -------- + --------- + ------------ + --------------- + 
| BUCode | ManagerID | B_Allocation | AllocatedAmount | 
+ -------- + --------- + ------------ + --------------- + 
| 42406016 | 5   | 10800.00  | 1293916.30  | 
| 42406016 | 5   | 661782.60 | 1723699.70  | 
| 42406016 | 5   | 2141987.20 | 4628466.40  | 
| 42406016 | 5   | 2163743.43 | 109956.12  | 
| 42406016 | 5   | 2163743.43 | 407655.00  | 
| 42406016 | 5   | 2163743.43 | 499902.00  | 
| 42406016 | 5   | 2163743.43 | 523275.55  | 
| 42406016 | 5   | 2163743.43 | 622954.76  | 
| 42406016 | 6   | 4747880.45 | 1500000.00  | 
| 42406016 | 6   | 4747880.45 | 2000000.00  | 
| 42406016 | 8   | 726893.75 | 14142.71  | 
| 42406016 | 8   | 726893.75 | 22143.56  | 
| 42406016 | 8   | 726893.75 | 106448.50  | 
| 42406016 | 8   | 726893.75 | 265501.45  | 
| 42406016 | 8   | 726893.75 | 318657.53  | 
| 42406016 | 14  | 4747880.45 | 747880.45  | 
+ -------- + --------- + ------------ + --------------- + 

Answer 1

はこれを試してみてください。

Declare @T1 Table(BUCode INT, ManagerID INT, B_Allocation Float,  AllocatedAmount Float); 
Declare @T2 Table(BUCode INT, ManagerID INT, B_Allocation Float,  AllocatedAmount Float); 
with cte as (**Add your Select statement here**) 

Insert Into @T1 
Select * from cte 

Insert Into @T2 
Select BUCode, ManagerID, sum(B_Allocation) from @T1 
Group By BUCode, ManagerID 

Select t2.BUCode, t2.ManagerID, t2.B_Allocation, t1.AllocatedAmount from @T1 as t1 
left join @T2 as t2 on t1.BUCode = t2.BUCode AND t1.ManagerID = t2.ManagerID