私自身の質問に答えているようです。
さらに調査するには、SourceDataLine
を使用することが、操作に十分な時間を与えたときにブロックされるため、移動する方法です。
適切なJavadocがないことにお詫びします。
class SoundPlayer
{
// plays an InputStream for a given number of samples, length
public static void play(InputStream stream, float sampleRate, int sampleSize, int length) throws LineUnavailableException
{
// you can specify whatever format you want...I just don't need much flexibility here
AudioFormat format = new AudioFormat(sampleRate, sampleSize, 1, false, true);
AudioInputStream audioStream = new AudioInputStream(stream, format, length);
Clip clip = AudioSystem.getClip();
clip.open(audioStream);
clip.start();
}
public static void play(InputStream stream, float sampleRate, int sampleSize) throws LineUnavailableException
{
AudioFormat format = new AudioFormat(sampleRate, sampleSize, 1, false, true);
SourceDataLine line = AudioSystem.getSourceDataLine(format);
line.open(format);
line.start();
// if you wanted to block, you could just run the loop in here
SoundThread soundThread = new SoundThread(stream, line);
soundThread.start();
}
private static class SoundThread extends Thread
{
private static final int buffersize = 1024;
private InputStream stream;
private SourceDataLine line;
SoundThread(InputStream stream, SourceDataLine line)
{
this.stream = stream;
this.line = line;
}
public void run()
{
byte[] b = new byte[buffersize];
// you could, of course, have a way of stopping this...
for (;;)
{
stream.read(b);
line.write(b, 0, buffersize);
}
}
}
}
私はこの回答を2日間で受け入れると思います。他の誰かがより良い解決策を提示しない限り。 – skeggse