XMLファイルから解析HTMLコンテンツに

Question

<xbrli:xbrl xmlns:aoi="http://www.aointl.com/20160331" xmlns:country="http://xbrl.sec.gov/country/2016-01-31" xmlns:currency="http://xbrl.sec.gov/currency/2016-01-31" xmlns:dei="http://xbrl.sec.gov/dei/2014-01-31" xmlns:exch="http://xbrl.sec.gov/exch/2016-01-31" xmlns:invest="http://xbrl.sec.gov/invest/2013-01-31" xmlns:iso4217="http://www.xbrl.org/2003/iso4217" xmlns:link="http://www.xbrl.org/2003/linkbase" xmlns:naics="http://xbrl.sec.gov/naics/2011-01-31" xmlns:nonnum="http://www.xbrl.org/dtr/type/non-numeric" xmlns:num="http://www.xbrl.org/dtr/type/numeric" xmlns:ref="http://www.xbrl.org/2006/ref" xmlns:sic="http://xbrl.sec.gov/sic/2011-01-31" xmlns:stpr="http://xbrl.sec.gov/stpr/2011-01-31" xmlns:us-gaap="http://fasb.org/us-gaap/2016-01-31" xmlns:us-roles="http://fasb.org/us-roles/2016-01-31" xmlns:us-types="http://fasb.org/us-types/2016-01-31" xmlns:utreg="http://www.xbrl.org/2009/utr" xmlns:xbrldi="http://xbrl.org/2006/xbrldi" xmlns:xbrldt="http://xbrl.org/2005/xbrldt" xmlns:xbrli="http://www.xbrl.org/2003/instance" xmlns:xlink="http://www.w3.org/1999/xlink" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> 
    <link:schemaRef xlink:href="aoi-20160331.xsd" xlink:type="simple"/> 
    <xbrli:context id="FD2016Q4YTD"> 
    <xbrli:entity> 
    <xbrli:identifier scheme="http://www.sec.gov/CIK">0000939930</xbrli:identifier> 
    </xbrli:entity> 
    <xbrli:period> 
    <xbrli:startDate>2015-04-01</xbrli:startDate> 
    <xbrli:endDate>2016-03-31</xbrli:endDate> 
    </xbrli:period> 
    </xbrli:context> 

    <aoi:OtherIncomeAndExpensePolicyTextBlock contextRef="FD2016Q4YTD" id="Fact-F51C7616E17E5B8B0B770D410BBF5A3E"> 
    <div style="font-family:Times New Roman;font-size:10pt;"><div style="line-height:120%;text-align:justify;font-size:10pt;"><font style="font-family:inherit;font-size:10pt;font-weight:bold;">Other Income (Expense)</font></div><div style="line-height:120%;text-align:justify;font-size:10pt;"><font style="font-family:inherit;font-size:10pt;"></font></div></div> 
    </aoi:OtherIncomeAndExpensePolicyTextBlock> 
    </xbrli:xbrl> 

This is My XML[XBRL], i need to parse this. This xml is my input and i don't know whether its a valid or not but in need output like this : 

    <div style="font-family:Times New Roman;font-size:10pt;"><div style="line-height:120%;text-align:justify;font-size:10pt;"><font style="font-family:inherit;font-size:10pt;font-weight:bold;">Other Income (Expense)</font></div><div style="line-height:120%;text-align:justify;font-size:10pt;"><font style="font-family:inherit;font-size:10pt;"></font></div></div> 

Please someone share me the knowledge for this problem i am facing from last two weeks. 

this is the code i am using 

    File fXmlFile = new File("/home/devteam-user1/Desktop/ky/UnitTesting.xml"); 
       DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance(); 
       DocumentBuilder dBuilder = dbFactory.newDocumentBuilder(); 
       Document doc = dBuilder.parse(fXmlFile); 

       XPath xPath = XPathFactory.newInstance().newXPath(); 
       final String DIV_UNDER_ROOT = "/*/aoi"; 
       NodeList divList = (NodeList)xPath.compile(DIV_UNDER_ROOT) 
         .evaluate(doc, XPathConstants.NODESET); 
       System.out.println(divList.getLength()); 
       for (int i = 0; i < divList.getLength() ; i++) { // just in case there is more than one 
        Node divNode = divList.item(i); 
        System.out.println(nodeToString(divNode)); 

//nodeToString method below 

    private static String nodeToString(Node node) throws Exception 
     { 
      Transformer transformer = TransformerFactory.newInstance().newTransformer(); 
      transformer.setOutputProperty(OutputKeys.INDENT, "yes"); 
      StreamResult result = new StreamResult(new StringWriter()); 
      transformer.transform(new DOMSource(node), result); 
      return result.getWriter().toString(); 
     } 

Answer 1

あなたの主な問題は

の下に「任意のノード2つのレベルに一致するXPath式です

final String DIV_UNDER_ROOT = "/*/aoi"; 

である

public static void main(String[] args) throws IOException { 
    FileInputStream fis = new FileInputStream("yourfile.xml"); 
    Document doc = Jsoup.parse(Utils.streamToString(fis)); 
    System.out.println(doc.select("aoi|OtherIncomeAndExpensePolicyTextBlock").html().toString()); 
} 

Answer 2

これが私のためによく働きますroot、ローカル名はaoiで、名前空間はありません "。これはあなたが望むものではありません。

"aoi"（つまり、 "http://www.aointl.com/20160331"名前空間に属していて、その名前が "OtherIncomeAndExpensePolicyTextBlock"であることを意味します）によってエイリアスが付けられた2レベルの深さのノードのコンテンツに一致します。

JavaでのXPathで

マッチングの名前空間は静かな面倒（XPath with namespace in JavaとHow to query XML using namespaces in Java with XPath?を参照）であるが、長い話を短く、あなたの代わりにこの方法を試みることができる：

final String DIV_UNDER_ROOT = "//*[local-name()='OtherIncomeAndExpensePolicyTextBlock' and namespace-uri()='http://www.aointl.com/20160331']/*"; 

あなたのDocumentBuilderFactoryが名前空間が認識されている場合にのみ動作します

DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance(); 
dbFactory.setNamespaceAware(true);