OracleのSQLのカンマで区切られたID

Question

私はそうのようなクエリがある：

SELECT 
    s.id, 
    CASE 
    WHEN INSTR(s.strain_value, '[') = 0 
    THEN s.strain_name 
    ELSE TRIM(SUBSTR(s.strain_name, 1, INSTR(s.strain_name, '[')-1)) 
    END AS strain_name 
FROM strain s 

はこれが私のように見えるテーブルを与える：

id  strain_name 
---------------------------------------------- 
100  CD-1 
101  CD-1 
102  CD-1 
200  SCID 
300  BusIp-hy 
301  BusIp-hy 
...  ... 

今、私はグループにstrain_nameことで結果の表を望んでいましたそして、次のようにカンマで区切ったidを得る：

id    strain_name 
---------------------------------------------- 
100, 101, 102 CD-1 
200    SCID 
300, 301  BusIp-hy 
...    ... 

私はこのクエリを試してみたが、私はありませんよtは私が欲しかったものを得る：

WITH q AS (
    SELECT 
    s.id, 
    CASE 
     WHEN INSTR(s.strain_name, '[') = 0 
     THEN s.strain_name 
     ELSE TRIM(SUBSTR(s.strain_name, 1, INSTR(s.strain_name, '[')-1)) 
    END AS strain_name 
    FROM strain s 
) 
SELECT (
    SELECT LISTAGG(id, ', ') 
    WITHIN GROUP (
    ORDER BY strain_name ASC 
) 
    FROM (SELECT DISTINCT strain_name FROM q) dc 
) AS id, strain_name 
FROM q 

あなたは、私は、各strain_nameについてidのカンマ区切りのリストを取得することができるように、私は最後のクエリを修正する助けてくださいことはできますか？

Answer 1

WITH q (id, strain_name) AS (
    SELECT id, 
     CASE WHEN INSTR(strain_value, '[') = 0 
       THEN strain_name 
       ELSE TRIM(SUBSTR(strain_name, 1, INSTR(strain_name, '[')-1)) 
     END 
    FROM strain 
) 
SELECT LISTAGG(id, ', ') WITHIN GROUP (ORDER BY id) AS id, 
     strain_name 
FROM q 
GROUP BY strain_name 

Answer 2

GROUP BYを試しましたか？

WITH q AS (
... 
) 
SELECT strain_name, listagg(id, ', ') within GROUP(ORDER BY id) 
FROM q 
GROUP BY strain_name 
ORDER BY strain_name 

Answer 3

WITH q AS (
    SELECT 
    s.id, 
    CASE 
     WHEN INSTR(s.strain_name, '[') = 0 
     THEN s.strain_name 
     ELSE TRIM(SUBSTR(s.strain_name, 1, INSTR(s.strain_name, '[')-1)) 
    END AS strain_name 
    FROM strain s 
) 
SELECT LISTAGG(id, ', ') WITHIN GROUP (ORDER BY id ASC) as id, q.strain_name 
    FROM q 
group by q.strain_name