Pythonの：ヶ月

Question

に戻り、以下の機能を小数の変換：あなたの毎月の支払いは6.25年のための$ 529.22、および$ 4620.06の頭金だろう。

私は小数点を0.25年の代わりに4か月に変換できますか。

私は、出力が読みたい：あなたの毎月の支払いは、6年と4ヶ月で$ 529.22、および$ 4620.06の頭金だろう。

あなたは月に12 *年は整数に変換し、小数部分を変換することができ

def newcar(): 

input("How much is a new car going to cost you per month? Please hit 
enter to start") 
p = int(input("Please enter total cost of car: ")) 
r = float(input("Please enter interest rate as a whole number(example: 
15.6% = 15.6): National average is around 10.5%): ")) 
t = int(input("These payments would last for how many months?: ")) 
dp = int(input("Please enter the downpayment percentage as a whole 
number: example: 20% = 20: ")) 
afterdp = p - (p * dp/100) 
downpay = p - afterdp 
downpay = round(downpay, 2) 
interest = afterdp * (r/100) * (t/12) 
interest = round(interest, 2) 
monthly_payment_bt = (afterdp + interest)/t 
monthly_payment_bt = round(monthly_payment_bt, 2) 
monthly_payment = (monthly_payment_bt * .07) + monthly_payment_bt 
monthly_payment = round(monthly_payment, 2) 
t = round(t/12, 2) 
return("Your monthly payment would be $" + str(monthly_payment) + " 
for " + str(t) + " years, and a downpayment of $" + str(downpay)) 

print(newcar()) 

Answer 1

：

def singular_or_plural(count, word): 
    if count == 1: 
     return "1 %s" % word 
    elif count > 1: 
     return "%d %ss" % (count, word) 


def years_and_months(float_year): 
    year = int(float_year) 
    month = int((float_year % 1) * 12) 
    words = [(year, 'year'), (month, 'month')] 
    return ' and '.join(singular_or_plural(count, word) 
         for (count, word) in words if count > 0) 

print(years_and_months(0.09)) 
print(years_and_months(0.50)) 
print(years_and_months(1)) 
print(years_and_months(2)) 
print(years_and_months(2.5)) 
print(years_and_months(2.99)) 
print(years_and_months(6.25)) 

それは出力：

1 month 
6 months 
1 year 
2 years 
2 years and 6 months 
2 years and 11 months 
6 years and 3 months 

このfonctionを呼び出す前に、あなたは可能性があり期間が少なくとも1ヶ月であることを確認してください。