このコードの長さを短くする方法はありますか？

Question

if (richTextBox1.Text.Contains("Home") == false) 
{    
    result_show.richTextBox1.Text += "Home in Home Menu is missing."; 
} 

if (richTextBox1.Text.Contains("Users") == false) 
{    
    result_show.richTextBox1.Text += "Users in Home Menu is missing."; 
} 

if (richTextBox1.Text.Contains("Space") == false) 
{    
    result_show.richTextBox1.Text += "Space in Home Menu is missing."; 
} 

https://stackoverflow.com/posts/39720620/ または、私の必要性の右に合った答えを表示するには、下にスクロールしてください。これを感謝します。

Answer 1

var list = new List<TextAndMessage>() 
{ 
    new TextAndMessage {TextToCompare = "Home", Message = "Home in Home Menu is missing."}, 
    new TextAndMessage {TextToCompare = "Users", Message = "Home in Home Menu is missing."} 
}; 

var sb = new StringBuilder(); 
foreach (var item in list) 
{ 
    if (!richTextBox1.Text.Contains(item.TextToCompare)) 
    { 
     sb.Append(item.Message); 
    } 
} 
//Assigning at the end, as you might falsely check that the string is contained in textbox, that has come from one of the messages. 
result_show.richTextBox1.Text = sb.ToString(); 

と

public class TextAndMessage 
{ 
    public string TextToCompare { get; set; } 
    public string Message { get; set; } 
} 

Answer 2

次のパターンを使用してください：

Dictionary<string, string> wordsToCompare = new Dictionary<string, string> 
{ 
    { "Home", "Home in Home Menu is missing." }, 
    { "Users", "Even another string here" }, 
    ... 
}; 

private string GetSuffixString(string word) 
{ 
    string resultString; 
    wordsToCompare.TryGetValue(word, out resultString); 
    return resultString; 
} 

をし、それを使用します。

StringBuilder builder = new StringBuilder(result_show.richTextBox1.Text); 
builder.Append(this.GetSuffixString(richTextBox1.Text)); 
result_show.richTextBox1.Text = builder.ToString(); 

Answer 3

Dictionary<string,string> Messages = new Dictionary<string,string> {"...."}; 

var sb = new StringBuilder(); 

Messages.ForEach(p=> 
{ 
    if(p.Key.Contains(richTextBox1.Text)) 
    { 
    sb.Append(P.value); 
    } 
}); 

Answer 4

string template = "{0} in Home Menu is missing."; 
string[] keywords = new string[] { "home", "users", "space" }; 
for (int i = 0; i < keywords.Length; i++) 
{ 
    result_show.richTextBox1.Text += richTextBox1.Text.Contains(keywords[i]) ? 
      string.Empty : string.Format(template, keywords[i]); 
} 

使用StringBuilderパフォーマンスが必要な場合