1つの列の値に基づいて行を作成する方法カンマ区切り

Question

Begin tran 

create table #user_det 
      (user_id varchar(50), emp_id int, role varchar(500)) 

insert into #user_det (user_id , emp_id , role) 
select 'Sankar', 431544 , '(Developer),(DBA),(Designer)' 
union all 
select 'Gowri', 145721 , '(DBA),(Designer)' 
union all 
select 'Raja', 101010 , 'ALL' 

select * from #user_det 

drop table #user_det 

Rollback 




OutPut Required: 
=============== 

select 'Sankar' as user_id ,431544 as emp_id ,'Developer' as Role 
union all 
select 'Sankar' as user_id ,431544 as emp_id ,'DBA' as Role 
union all 
select 'Sankar' as user_id ,431544 as emp_id ,'Designer' as Role 
union all 
select 'Gowri' as user_id ,145721 as emp_id ,'DBA' as Role 
union all 
select 'Gowri' as user_id ,145721 as emp_id ,'Designer' as Role 
union all 
select 'Raja' as user_id ,101010 as emp_id ,'ALL' as Role 

Answer 1

string_split()を使用できます。

select user_id, emp_id, Role = replace(replace(s.Item,'(',''),')','') 
from #user_det u 
    cross apply dbo.delimitedsplit8K(u.role,',') s 

rextesterデモ：http://rextester.com/YVXGU42109

戻り値：

+---------+--------+-----------+ 
| user_id | emp_id | Role | 
+---------+--------+-----------+ 
| Sankar | 431544 | Developer | 
| Sankar | 431544 | DBA  | 
| Sankar | 431544 | Designer | 
| Gowri | 145721 | DBA  | 
| Gowri | 145721 | Designer | 
| Raja | 101010 | ALL  | 
+---------+--------+-----------+ 

分割ストリングが参照ジェフMODENによってCSVスプリッタテーブル値関数を使用してSQL Serverプレ2016年

：

• Tally OH! An Improved SQL 8K “CSV Splitter” Function - Jeff Moden
• Splitting Strings : A Follow-Up - Aaron Bertrand
• Split strings the right way – or the next best way - Aaron Bertrand
• string_split() in SQL Server 2016 : Follow-Up #1 - Aaron Bertrand

---

delimitedsplit8KジェフMODENによって機能：

create function [dbo].[delimitedsplit8K] (
     @pstring varchar(8000) 
    , @pdelimiter char(1) 
) 
returns table with schemabinding as 
return 
    with e1(N) as (
    select 1 union all select 1 union all select 1 union all 
    select 1 union all select 1 union all select 1 union all 
    select 1 union all select 1 union all select 1 union all select 1 
) 
    , e2(N) as (select 1 from e1 a, e1 b) 
    , e4(N) as (select 1 from e2 a, e2 b) 
    , ctetally(N) as (
    select top (isnull(datalength(@pstring),0)) 
     row_number() over (order by (select null)) from e4 
) 
    , ctestart(N1) as (
    select 1 union all 
    select t.N+1 from ctetally t where substring(@pstring,t.N,1) = @pdelimiter 
) 
    , ctelen(N1,L1) as (
    select s.N1, 
     isnull(nullif(charindex(@pdelimiter,@pstring,s.N1),0)-s.N1,8000) 
    from ctestart s 
) 
select itemnumber = row_number() over(order by l.N1) 
     , item  = substring(@pstring, l.N1, l.L1) 
    from ctelen l 
; 
go 

Answer 2

SqlZimがにリンクされて誰もが良いスプリット/解析機能を持っている必要があります。あなたは

Select A.user_id 
     ,A.emp_id 
     ,[role] = Replace(Replace(B.RetVal,')',''),'(','') 
From #user_det A 
Cross Apply (
       Select RetSeq = Row_Number() over (Order By (Select null)) 
         ,RetVal = LTrim(RTrim(B.i.value('(./text())[1]', 'varchar(max)'))) 
       From (Select x = Cast('<x>' + replace((Select replace(A.[Role],',','§§Split§§') as [*] For XML Path('')),'§§Split§§','</x><x>')+'</x>' as xml).query('.')) as X 
       Cross Apply x.nodes('x') AS B(i) 
      ) B 

を望んでいないか、UDF

を使用することができない場合はここで

は別のオプションです戻り