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現在、アイソサーフェス抽出アルゴリズムを研究中です。私はここでintroductionが見つかりました。Javascriptコードです。私はJavascriptのコーダーではないことに気付かなければならない。私は主にJavaとF＃ですが、コードをF＃に移植することができました。ナイーブサーフェスネットアルゴリズムのワークフロー
私のすべての問題は現在、サーフェスネットアルゴリズムの実装を理解しています。 （リンクは下にあります）。それはブログ/紹介の作者によって作られたものです。
197ライン（169 SLOC）here
// The MIT License (MIT)
//
// Copyright (c) 2012-2013 Mikola Lysenko
//
// Permission is hereby granted, free of charge, to any person obtaining a copy
// of this software and associated documentation files (the "Software"), to deal
// in the Software without restriction, including without limitation the rights
// to use, copy, modify, merge, publish, distribute, sublicense, and/or sell
// copies of the Software, and to permit persons to whom the Software is
// furnished to do so, subject to the following conditions:
//
// The above copyright notice and this permission notice shall be included in
// all copies or substantial portions of the Software.
//
// THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
// IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
// FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
// AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
// LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,
// OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN
// THE SOFTWARE.
/**
* SurfaceNets in JavaScript
*
* Written by Mikola Lysenko (C) 2012
*
* MIT License
*
* Based on: S.F. Gibson, "Constrained Elastic Surface Nets". (1998) MERL Tech Report.
*/
var SurfaceNets = (function() {
"use strict";
//Precompute edge table, like Paul Bourke does.
// This saves a bit of time when computing the centroid of each boundary cell
var cube_edges = new Int32Array(24)
, edge_table = new Int32Array(256);
(function() {
//Initialize the cube_edges table
// This is just the vertex number of each cube
var k = 0;
for(var i=0; i<8; ++i) {
for(var j=1; j<=4; j<<=1) {
var p = i^j;
if(i <= p) {
cube_edges[k++] = i;
cube_edges[k++] = p;
}
}
}
//Initialize the intersection table.
// This is a 2^(cube configuration) -> 2^(edge configuration) map
// There is one entry for each possible cube configuration, and the output is a 12-bit vector enumerating all edges crossing the 0-level.
for(var i=0; i<256; ++i) {
var em = 0;
for(var j=0; j<24; j+=2) {
var a = !!(i & (1<<cube_edges[j]))
, b = !!(i & (1<<cube_edges[j+1]));
em |= a !== b ? (1 << (j >> 1)) : 0;
}
edge_table[i] = em;
}
})();
//Internal buffer, this may get resized at run time
var buffer = new Int32Array(4096);
return function(data, dims) {
var vertices = []
, faces = []
, n = 0
, x = new Int32Array(3)
, R = new Int32Array([1, (dims[0]+1), (dims[0]+1)*(dims[1]+1)])
, grid = new Float32Array(8)
, buf_no = 1;
//Resize buffer if necessary
if(R[2] * 2 > buffer.length) {
buffer = new Int32Array(R[2] * 2);
}
//March over the voxel grid
for(x[2]=0; x[2]<dims[2]-1; ++x[2], n+=dims[0], buf_no ^= 1, R[2]=-R[2]) {
//m is the pointer into the buffer we are going to use.
//This is slightly obtuse because javascript does not have good support for packed data structures, so we must use typed arrays :(
//The contents of the buffer will be the indices of the vertices on the previous x/y slice of the volume
var m = 1 + (dims[0]+1) * (1 + buf_no * (dims[1]+1));
for(x[1]=0; x[1]<dims[1]-1; ++x[1], ++n, m+=2)
for(x[0]=0; x[0]<dims[0]-1; ++x[0], ++n, ++m) {
//Read in 8 field values around this vertex and store them in an array
//Also calculate 8-bit mask, like in marching cubes, so we can speed up sign checks later
var mask = 0, g = 0, idx = n;
for(var k=0; k<2; ++k, idx += dims[0]*(dims[1]-2))
for(var j=0; j<2; ++j, idx += dims[0]-2)
for(var i=0; i<2; ++i, ++g, ++idx) {
var p = data[idx];
grid[g] = p;
mask |= (p < 0) ? (1<<g) : 0;
}
//Check for early termination if cell does not intersect boundary
if(mask === 0 || mask === 0xff) {
continue;
}
//Sum up edge intersections
var edge_mask = edge_table[mask]
, v = [0.0,0.0,0.0]
, e_count = 0;
//For every edge of the cube...
for(var i=0; i<12; ++i) {
//Use edge mask to check if it is crossed
if(!(edge_mask & (1<<i))) {
continue;
}
//If it did, increment number of edge crossings
++e_count;
//Now find the point of intersection
var e0 = cube_edges[ i<<1 ] //Unpack vertices
, e1 = cube_edges[(i<<1)+1]
, g0 = grid[e0] //Unpack grid values
, g1 = grid[e1]
, t = g0 - g1; //Compute point of intersection
if(Math.abs(t) > 1e-6) {
t = g0/t;
} else {
continue;
}
//Interpolate vertices and add up intersections (this can be done without multiplying)
for(var j=0, k=1; j<3; ++j, k<<=1) {
var a = e0 & k
, b = e1 & k;
if(a !== b) {
v[j] += a ? 1.0 - t : t;
} else {
v[j] += a ? 1.0 : 0;
}
}
}
//Now we just average the edge intersections and add them to coordinate
var s = 1.0/e_count;
for(var i=0; i<3; ++i) {
v[i] = x[i] + s * v[i];
}
//Add vertex to buffer, store pointer to vertex index in buffer
buffer[m] = vertices.length;
vertices.push(v);
//Now we need to add faces together, to do this we just loop over 3 basis components
for(var i=0; i<3; ++i) {
//The first three entries of the edge_mask count the crossings along the edge
if(!(edge_mask & (1<<i))) {
continue;
}
// i = axes we are point along. iu, iv = orthogonal axes
var iu = (i+1)%3
, iv = (i+2)%3;
//If we are on a boundary, skip it
if(x[iu] === 0 || x[iv] === 0) {
continue;
}
//Otherwise, look up adjacent edges in buffer
var du = R[iu]
, dv = R[iv];
//Remember to flip orientation depending on the sign of the corner.
if(mask & 1) {
faces.push([buffer[m], buffer[m-du], buffer[m-du-dv], buffer[m-dv]]);
} else {
faces.push([buffer[m], buffer[m-dv], buffer[m-du-dv], buffer[m-du]]);
}
}
}
}
//All done! Return the result
return { vertices: vertices, faces: faces };
};
})();
私はここに書きます私が理解しないと、どのような私には不明であるから6.38キロバイト：
私はアルゴリズムを理解する方法：
cube_edges（またはむしろ頂点リスト）の組み合わせリストとエッジリスト（ルックアップテーブル）を作成する
現在のセル/キューブの各頂点の浮動小数点数をトポロジに従って（エッジリストに依存して）補間しながら、完全なグリッドを反復処理します。
頂点を押し戻し、面を設定します。
私には不明だ何
：
- 私はすでにedges_tableを生成するアルゴリズムをインターネットで検索するが、私は1つを発見していません。誰かが私にそれを説明することができますか？
- どのように面が互いに接続されていますか。顔が作られた最後のスニペットではどうなりますか？
私はルールに合わせて質問を改善しています。私はあなたが引用コードを読んでいないが、あなたの質問に答えるために