結果の間隔PHP Mysql

Question

私は以下のコードを持っています。

PHPに完全に新しいIMとMySQL

<table align="center" border="0" width="100%"> 
<tr> 
<th>id</th> 
    <th>Staff Name</th> 
    <th>Date</th> 
    <th>Reason</th> 
</tr> 

<?php 

    $startdate = $_SESSION['startdate']; 
    $enddate = $_SESSION['enddate']; 

    $code = mysql_query("SELECT id, name, UNIX_TIMESTAMP(date) AS date, reason FROM taken WHERE date BETWEEN '$startdate' AND '$enddate' ORDER BY date ASC"); 


    while($row = mysql_fetch_array($code)) { 



echo "\t<tr><td>{$row['id']} ". 
"</td><td>{$row['name']} ". 
"</td><td>" . date("d/m/Y", $row['date']) ."". 
    "</td><td>{$row['reason']} </td></tr>\n"; 

それは、以下の結果を生成するが、私は、日付変更の間にスペースを入れたいです。 I.Eスペース/休憩28/05/2016 & 29/05/26。

ご協力いただければ幸いです。あなたがPHPに新しいですが

id Staff Name Date Reason 
1296 28/05/2016 Holiday 
1832 28/05/2016 Holiday 
1330 28/05/2016 Holiday 
825 28/05/2016 Holiday 
1858 28/05/2016 Holiday 
849 28/05/2016 Holiday 
1958 28/05/2016 Holiday 
2022 28/05/2016 Holiday 
1263 28/05/2016 Holiday 
1331 29/05/2016 Holiday 
826 29/05/2016 Holiday 
1959 29/05/2016 Holiday 
2023 29/05/2016 Holiday 
1264 29/05/2016 Holiday 
1332 30/05/2016 Holiday 
827 30/05/2016 Holiday 
1960 30/05/2016 Holiday 
2024 30/05/2016 Holiday 
1265 30/05/2016 Holiday 
533 31/05/2016 Holiday 
1843 31/05/2016 Holiday 
52 31/05/2016 Holiday 
1420 31/05/2016 Holiday 
1679 31/05/2016 Holiday 
1938 31/05/2016 Holiday 
936 31/05/2016 Holiday 
231 31/05/2016 Holiday 

Answer 1

コードは、空の行

$save = null; 
while($row = mysql_fetch_array($code)) { 
    $date = date("d/m/Y", $row['date']; 
    if ($save && $date != $save) { 
     $save = $date; 
     echo "\t<tr><td cplspan="4">&nbsp;</td></tr>\n" 
    } 
    echo "\t<tr><td>{$row['id']} ". 
     "</td><td>{$row['name']} ". 
     "</td><td>$date</td><td>{$row['reason']} </td></tr>\n"; 
}