Javaスレッド完了ステータス

Question

私は2つのスレッドt1とt2を持っていますが、それぞれ個別のタスクを実行します。

スレッドt1のタスクの60％完了後にスレッドt2を開始したいとします。

どのように私はそれを達成することができます誰か考えがありますか？

Answer 1

@Test 
public void test() throws InterruptedException{ 
    Thread t = new Thread(new Task1()); 

    t.start(); 

    t.join(0); 

    //keep in mind that t2 can still be running at this point 
    System.out.println("done running task1."); 
} 

public static class Task1 implements Runnable{ 

    public void run(){ 
     //Smimulate some long running job. In your case you need to have your own logic of checking if t1 is 60% done. 
     //In this case we just wait 0.5 seconds for each 10% of work done 
     for (int i = 0; i < 10; i++){ 

      try { Thread.sleep(500); } 
      catch (InterruptedException e) { throw new RuntimeException(e); } 

      int percentComplete = i*10; 

      System.out.println("Completed " + percentComplete + "%."); 

      if (percentComplete == 60){ 
       new Thread(new Task2()).start(); //this how to start t2 when we are 60% complete 
      } 
     }    
    } 
} 

public static class Task2 implements Runnable{ 

    @Override 
    public void run() { 
     //simulate t2 task that will run for 5 seconds. 

     System.out.println("task2 started."); 

     try { Thread.sleep(5000); } 
     catch (InterruptedException e) { throw new RuntimeException(e); } 

     System.out.println("task2 is done."); 
    } 

} 

Answer 2

T1は60％完了したら知ることができますか？もしそうなら、その時にT2を始めるのはなぜですか？

Thread t2 = null; 

class T2task implements Runnable { 
    ... 
} 

class T1task implements Runnable { 
    @Override 
    public void run() { 
     while (isNotFinished(...)) { 
      if (isAtLeast60PercentDone(...) && t2 != null) { 
       t2 = new Thread(new T2task(...)); 
       t2.start(); 
      } 
      doSomeMoreWork(...); 
     } 
    } 
}