2011-11-24 13 views
9

私は列リストの定数を選択しているので、適切な列挙型に文字列を変換するためのaliasToBeanが必要です。Hibernate aliasToBeanは文字列をEnumに変換しません

私は文字列としてenumプロパティを持つ他のエンティティをマップしていますが、問題はありません。

@SuppressWarnings("unchecked") 
    List<AssociatedEntity> fileList = queryUtil.createHQLQuery((
      "select '" + AssociatedEntityTypeEnum.ASSOCIATED_ENTITY_TYPE_FILE + "' as associatedEntityType," + 
      " a.file2Id as id," + 
      " f.name as name" + 
      " from File f, Association a" + 
      " where f.id = :fileId" + 
      " and a.file1Id = f.id" + 
      " and a.associationType = :associationType" 
    )) 
    .setParameter("fileId", fileId) 
    .setParameter("associationType", AssociationTypeEnum.ASSOCIATION_TYPE_FILE_FILE) 
    .setResultTransformer(Transformers.aliasToBean(AssociatedEntity.class)) 
    .list(); 

これはBeanです:

public class AssociatedEntity { 

public AssociatedEntity() {} 

@Enumerated(EnumType.STRING) 
private AssociatedEntityTypeEnum associatedEntityType; 
public AssociatedEntityTypeEnum getAssociatedEntityType() { return this.associatedEntityType; } 
public void setAssociatedEntityType(AssociatedEntityTypeEnum associatedEntityType) { this.associatedEntityType = associatedEntityType; } 

private Integer id; 
public Integer getId() { return this.id; } 
public void setId(Integer id) { this.id = id; } 

private String name; 
public void setName(String name) { this.name = name; } 
public String getName() { return this.name; } 

} 

、ここではエラーは以下のとおりです。フィールドの上に列挙ハンドラを作成し、指定する方法

23.11.2011 17:05:25 INFO [http-8080-2] (QueryUtil:createHQLQuery) - select 'ASSOCIATED_ENTITY_TYPE_FILE' as associatedEntityType, a.file2Id as id, f.name as name from File f, Association a where f.id = :fileId and a.file1Id = f.id and a.associationType = :associationType 
23.11.2011 17:05:25 ERROR [http-8080-2] (BasicPropertyAccessor$BasicSetter:set) - IllegalArgumentException in class: com.twoh.dto.AssociatedEntity, setter method of property: associatedEntityType 
23.11.2011 17:05:25 ERROR [http-8080-2] (BasicPropertyAccessor$BasicSetter:set) - expected type: com.twoh.dto.enums.AssociatedEntityTypeEnum, actual value: java.lang.String 

答えて

2

SOの回答から見つけた解決策は次のとおりです

Properties params = new Properties(); 
     params.put("enumClass", "models.IOStatusEnum"); 
     params.put("type", "12"); /*type 12 instructs to use the String representation of enum value*/ 
     Type myEnumType = new TypeLocatorImpl(new TypeResolver()).custom(EnumType.class, params); 
     SQLQuery q = sess.createSQLQuery(queryString).addScalar("status", myEnumType);; 
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