セミコロンの構文エラー？

Question

私のGCSE作業用のメニューをプログラムしようとしていますが、セミコロンで構文エラーが発生します。ここ は以下のプログラムです：

def choice() : 
    print = ("Welcome to the troubleshooting System") 
    print = ("") 
    print = ("a. Samsung") 
    print = ("") 
    print = ("b. Android") 
    print = ("") 
    print = ("c. Apple") 
    print = ("") 
    print = ("d. Blackberry") 
    print = ("") 
    print = ("e. Sony") 
    choice_input = input(str(" Please select the letter of the brand of phone that you are using") 

         if choice_input == "a": 
         Samsung() 

         elif choice_input == "b": 
          Android() 

         elif choice_input == "c": 
          Apple() 

         elif choice_input == "d": 
          Blackberry() 

         elif choice_input == "e": 
          Sony() 

私は問題は「choice_input場合== 『A』：」であると思います助けてください！

Answer 1

あなたは主に印刷機能をいくつか間違えました。なぜあなたは印刷文を呼び出す代わりに印刷変数を作成していますか？ここで見る：

import time 
import sys 
#The program boots up 
print("Loading...") 
time.sleep(2) 
# 'Def' allows this program to present a menu toward the user in which he can decide what phone 

def choice() : 
    print ("Welcome to the troubleshooting System") 
    print ("") 
    print ("a. Samsung") 
    print ("") 
    print ("b. Android") 
    print ("") 
    print ("c. Apple") 
    print ("") 
    print ("d. Blackberry") 
    print ("") 
    print ("e. Sony") 
    choice_input = input(str(" Please select the letter of the brand of phone that you are using")) 
    if choice_input == "a": 
     Samsung() 

    elif choice_input == "b": 
     Android() 

    elif choice_input == "c": 
     Apple() 

    elif choice_input == "d": 
     Blackberry() 

    elif choice_input == "e": 
     Sony() 

choice()#call the function to start/execute