テーブルを結合する@OneToMany/@ManyToOne

Question

テーブルを結合しようとしている小さな割り当てです。私はMySQLの& Javaでいくつかの経験を持っていますが、Spring、Hibernate & HSQLには新しいです。私が働いてきた

は、私がすでに作成されますが、何のプロイムず、フレームワークがない巨大な変更が、イム問題はもうどこにあるかわからない...だけでなく私に新しいです...

前に合流しますいくつかのテーブルを結合してクラスを関連付けることができましたが、すべての顧客レコードに従業員IDへの外部キーが必要です。私はいくつかの異なる設定を試みたが、役に立たなかった。ここで私は今どこにいるのだろうか？次のエラーが供給

イム：

java.lang.IllegalStateException: Failed to load ApplicationContext 

at org.springframework.test.context.DefaultCacheAwareContextLoaderDelegate.loadContext(DefaultCacheAwareContextLoaderDelegate.java:94) 
at org.springframework.test.context.DefaultTestContext.getApplicationContext(DefaultTestContext.java:72) 
at org.springframework.test.context.support.DependencyInjectionTestExecutionListener.injectDependencies(DependencyInjectionTestExecutionListener.java:117) 
at org.springframework.test.context.support.DependencyInjectionTestExecutionListener.prepareTestInstance(DependencyInjectionTestExecutionListener.java:83) 
at org.springframework.test.context.TestContextManager.prepareTestInstance(TestContextManager.java:212) 
at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.createTest(SpringJUnit4ClassRunner.java:200) 
at org.springframework.test.context.junit4.SpringJUnit4ClassRunner$1.runReflectiveCall(SpringJUnit4ClassRunner.java:259) 
at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:12) 
at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.methodBlock(SpringJUnit4ClassRunner.java:261) 
at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.runChild(SpringJUnit4ClassRunner.java:219) 
at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.runChild(SpringJUnit4ClassRunner.java:83) 
at org.junit.runners.ParentRunner$3.run(ParentRunner.java:290) 
at org.junit.runners.ParentRunner$1.schedule(ParentRunner.java:71) 
at org.junit.runners.ParentRunner.runChildren(ParentRunner.java:288) 
at org.junit.runners.ParentRunner.access$000(ParentRunner.java:58) 
at org.junit.runners.ParentRunner$2.evaluate(ParentRunner.java:268) 
at org.springframework.test.context.junit4.statements.RunBeforeTestClassCallbacks.evaluate(RunBeforeTestClassCallbacks.java:61) 
at org.springframework.test.context.junit4.statements.RunAfterTestClassCallbacks.evaluate(RunAfterTestClassCallbacks.java:68) 
at org.junit.runners.ParentRunner.run(ParentRunner.java:363) 
at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.run(SpringJUnit4ClassRunner.java:163) 
at org.junit.runner.JUnitCore.run(JUnitCore.java:137) 
at com.intellij.junit4.JUnit4IdeaTestRunner.startRunnerWithArgs(JUnit4IdeaTestRunner.java:117) 
at com.intellij.junit4.JUnit4IdeaTestRunner.startRunnerWithArgs(JUnit4IdeaTestRunner.java:42) 
at com.intellij.rt.execution.junit.JUnitStarter.prepareStreamsAndStart(JUnitStarter.java:262) 
at com.intellij.rt.execution.junit.JUnitStarter.main(JUnitStarter.java:84) 
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) 
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62) 
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) 
at java.lang.reflect.Method.invoke(Method.java:498) 
at com.intellij.rt.execution.application.AppMain.main(AppMain.java:147) 

Caused by: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'entityManagerFactory' defined in nl.mad.w2l2.ApplicationConfig: Invocation of init method failed; nested exception is javax.persistence.PersistenceException: [PersistenceUnit: default] Unable to build Hibernate SessionFactory 
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1574) 
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:539) 
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:476) 
at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:303) 
at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:230) 
at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:299) 
at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:194) 
at org.springframework.context.support.AbstractApplicationContext.getBean(AbstractApplicationContext.java:956) 
at org.springframework.context.support.AbstractApplicationContext.finishBeanFactoryInitialization(AbstractApplicationContext.java:747) 
at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:480) 
at org.springframework.test.context.support.AbstractGenericContextLoader.loadContext(AbstractGenericContextLoader.java:125) 
at org.springframework.test.context.support.AbstractGenericContextLoader.loadContext(AbstractGenericContextLoader.java:60) 
at org.springframework.test.context.support.AbstractDelegatingSmartContextLoader.delegateLoading(AbstractDelegatingSmartContextLoader.java:109) 
at org.springframework.test.context.support.AbstractDelegatingSmartContextLoader.loadContext(AbstractDelegatingSmartContextLoader.java:261) 
at org.springframework.test.context.DefaultCacheAwareContextLoaderDelegate.loadContextInternal(DefaultCacheAwareContextLoaderDelegate.java:68) 
at org.springframework.test.context.DefaultCacheAwareContextLoaderDelegate.loadContext(DefaultCacheAwareContextLoaderDelegate.java:86) 
... 29 more 

Caused by: javax.persistence.PersistenceException: [PersistenceUnit: default] Unable to build Hibernate SessionFactory 
at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.persistenceException(EntityManagerFactoryBuilderImpl.java:1239) 
at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.access$600(EntityManagerFactoryBuilderImpl.java:120) 
at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl$4.perform(EntityManagerFactoryBuilderImpl.java:855) 
at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl$4.perform(EntityManagerFactoryBuilderImpl.java:845) 
at org.hibernate.boot.registry.classloading.internal.ClassLoaderServiceImpl.withTccl(ClassLoaderServiceImpl.java:398) 
at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.build(EntityManagerFactoryBuilderImpl.java:844) 
at org.hibernate.jpa.HibernatePersistenceProvider.createContainerEntityManagerFactory(HibernatePersistenceProvider.java:152) 
at org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean.createNativeEntityManagerFactory(LocalContainerEntityManagerFactoryBean.java:343) 
at org.springframework.orm.jpa.AbstractEntityManagerFactoryBean.afterPropertiesSet(AbstractEntityManagerFactoryBean.java:318) 
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1633) 
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1570) 
... 44 more 

Caused by: org.hibernate.AnnotationException: Illegal attempt to map a non collection as a @OneToMany, @ManyToMany or @CollectionOfElements: nl.mad.w2l2.model.Employee.bsn 
at org.hibernate.cfg.annotations.CollectionBinder.getCollectionBinder(CollectionBinder.java:330) 
at org.hibernate.cfg.AnnotationBinder.processElementAnnotations(AnnotationBinder.java:1922) 
at org.hibernate.cfg.AnnotationBinder.processIdPropertiesIfNotAlready(AnnotationBinder.java:963) 
at org.hibernate.cfg.AnnotationBinder.bindClass(AnnotationBinder.java:796) 
at org.hibernate.cfg.Configuration$MetadataSourceQueue.processAnnotatedClassesQueue(Configuration.java:3845) 
at org.hibernate.cfg.Configuration$MetadataSourceQueue.processMetadata(Configuration.java:3799) 
at org.hibernate.cfg.Configuration.secondPassCompile(Configuration.java:1412) 
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1846) 
at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl$4.perform(EntityManagerFactoryBuilderImpl.java:852) 
... 52 more 

最後のエラーは、私はイムが参加すると何か間違ったことと信じています。私は検索して検索したり、チュートリアルや2を試しましたが、私は何かを見落としていると思います...私は問題をピンポイントするためにコードの大部分を書き直して削除しましたが、 ！noobish間違いや見落とし、事前にとても残念&感謝:)

抽象Userクラス：

@Entity 
@Table(name = "user") 
@Inheritance(strategy = JOINED) 
@DiscriminatorColumn(name = "type") 
public abstract class User extends BaseEntity { 

private String email; 

サブクラスの従業員

@Entity 
//@Table(name = "employee") 
@DiscriminatorValue("employee") 
@PrimaryKeyJoinColumn(name = "user_id") 
public class Employee extends User { 

@OneToMany 
@JoinColumn(name="accountant_id") 

private String bsn; 

サブクラスカスタマー

@Entity 
//@Table(name = "customer") 
@DiscriminatorValue("customer") 
@PrimaryKeyJoinColumn(name = "user_id") 
public class Customer extends User { 

@ManyToOne 
@JoinColumn(name="id") 

private BigDecimal balance; 

そして、私のデータベースの作成スキーム

-- user -- 
CREATE TABLE public.user (
    id BIGINT IDENTITY, 
    type VARCHAR (50) NOT NULL, 
    email VARCHAR (50) NOT NULL, 
); 
CREATE UNIQUE INDEX ix_user_email ON public.user(email); 

-- customer -- 
CREATE TABLE public.customer (
    id BIGINT IDENTITY, 
    user_id BIGINT NOT NULL, 
    accountant_id BIGINT, 
    balance NUMERIC(19,2) NOT NULL, 
); 
ALTER TABLE public.customer 
    ADD CONSTRAINT fk_customer_user_id FOREIGN KEY (user_id) REFERENCES public.user(id); 
ALTER TABLE public.customer 
    ADD CONSTRAINT fk_customer_employee_id FOREIGN KEY (accountant_id) REFERENCES public.user(id); 


-- employee -- 
CREATE TABLE public.employee (
    id BIGINT IDENTITY, 
    user_id BIGINT NOT NULL, 
    bsn VARCHAR(9) NOT NULL 
); 
ALTER TABLE public.employee 
    ADD CONSTRAINT fk_employee_user_id FOREIGN KEY (user_id) REFERENCES public.user(id); 
CREATE UNIQUE INDEX ix_employee_bsn ON public.employee(bsn); 

事前に多くの多くのTHANKS！

Answer 1

エラーは言う：@OneToMany、@ManyToManyまたは@CollectionOfElementsのような非コレクションをマッピングする

不正な試みを：nl.mad.w2l2.model.Employee.bsn

対応するコードは

@OneToMany 
@JoinColumn(name="accountant_id") 
private String bsn; 

です。それは意味がありません。 OneToManyは、1人のEmployee（例えば）が多くのタスクを持ち、これらの各タスクがこの従業員だけに属していることをHibernateに伝えるために使用されます。障害がセッションファクトリの作成に表示されている理由、それは移動しようとする上で表示されるはずのかかわら例

@OneToMany 
private Set<Task> tasks;