複数の日付の差分（C言語）＃

Question

ここで唯一の矛盾は、2つのendDate（コードで10,15）のmin値が同じstartDate（25）になる場合です。

解決策：これらの2分のうち最小値を取りたいです。競合するendDateによって指定される値。私はあなたの質問が悪い私は、私はあなたがやろうとしているかを理解するために管理信じて提示されている上で上記の紳士に同意しないが

public class DateController : Controller 
    public ActionResult date() 
    { 
     int allDiff; 
     List<int> list=new List<int>(); 
     int flag = 0; 

     DateTime[] startDate = new DateTime[3]; 
     startDate[0] = new DateTime(2011, 11, 5); 
     startDate[1] = new DateTime(2011, 11, 7); 
     startDate[2] = new DateTime(2011, 11, 25); 

     DateTime[] endDate = new DateTime[3]; 
     endDate[0] = new DateTime(2011, 11, 10); 
     endDate[1] = new DateTime(2011, 11,15); 
     endDate[2] = new DateTime(2011, 11, 30); 
     DateTime Min= startDate.Min(); 
     DateTime Max = endDate.Max(); 

     TimeSpan span = Max - Min; 
     int total = span.Days; 
     ViewBag.globalTotal = total; 


     foreach (DateTime e in endDate) 
     { 

      foreach (DateTime s in startDate) 
      { 
       if (s >= e) 
       { 
        TimeSpan span1 = s - e; 
        allDiff = span1.Days; 
        list.Add(allDiff); 
        flag = 1; 

       } 
       else { 
        flag = 0; 
       } 

      } 
      if (flag == 1) 
      { 
       int m = list.Min(); 
       ViewBag.dhiraj = m; 
       total = total - m; 
       list.Clear(); 
      } 

     } 
     ViewBag.Total = total; 

     return View(); 
    } 

Answer 1

作業コード

public ActionResult date() 
    { 
     int j = 0; 
     int output = 0; 
     DateTime[] startDate = new DateTime[6]; 

     startDate[0] = new DateTime(2011, 11, 1); 
     startDate[1] = new DateTime(2011, 11, 6); 
     startDate[2] = new DateTime(2011, 11, 16); 
     startDate[3] = new DateTime(2011, 11, 17); 
     startDate[4] = new DateTime(2011, 11, 17); 
     startDate[5] = new DateTime(2011, 11, 17); 




     DateTime[] endDate = new DateTime[6]; 
     endDate[0] = new DateTime(2011, 11, 4); 
     endDate[1] = new DateTime(2011, 11, 8); 
     endDate[2] = new DateTime(2011, 11, 18); 
     endDate[3] = new DateTime(2011, 11, 17); 
     endDate[4] = new DateTime(2011, 11, 22); 
     endDate[5] = new DateTime(2011, 11, 19); 

     //5-7 
               //7-9 
               //15-20 
     List<DateTime> start = new List<DateTime>(); 
     List<DateTime> end = new List<DateTime>(); 

     DateTime interStart = default(DateTime); 
     DateTime interEnd = default(DateTime);//initialize 
     start.Add(interStart); 
     end.Add(interEnd); 



     for (int i = 0; i < startDate.Length ; i++) 
     { 
      if(i < (startDate.Length-1)){ 
       j=i+1; 
      } 
      else{ 
       j = i; 
      } 

      if ((startDate[i] <= endDate[j]) && (endDate[i] >= startDate[j])) 
      { 


       List<DateTime> intermediateStart = new List<DateTime>(); 
       intermediateStart.Add(startDate[i]); 
       intermediateStart.Add(startDate[j]); 
       interStart = intermediateStart.Min(); 
       List<DateTime> intermediateEnd = new List<DateTime>(); 
       intermediateEnd.Add(endDate[i]); 
       intermediateEnd.Add(endDate[j]); 
       interEnd = intermediateEnd.Max(); 


       if ((start.Last() <= interEnd) && (end.Last() >= interStart)) 
       { 

         List<DateTime> finalStartValue = new List<DateTime>(); 
         finalStartValue.Add(start.Last()); 
         finalStartValue.Add(interStart); 
         List<DateTime> finalEndValue = new List<DateTime>(); 
         finalEndValue.Add(end.Last()); 
         finalEndValue.Add(interEnd); 

         DateTime finalStart = finalStartValue.Min(); 
         DateTime finalEnd = finalEndValue.Max(); 


         start.Remove(start.Last()); 
         end.Remove(end.Last()); 
         start.Add(finalStart); 
         end.Add(finalEnd); 
       } 
       else 
       { 
        start.Add(interStart); 
        end.Add(interEnd); 
       } 

      } 
      else 
      { 
       start.Add(startDate[i]); 
       end.Add(endDate[i]); 
       //remove(start.first); 
      } 
     } 
     int count=(start.Count())-1; 
     for (int k = 0; k <= count; k++) { 
      TimeSpan span = end[k]-start[k]; 
      int diff = span.Days; 
      output = diff + output; 

     } 


      ViewBag.finalOutput = output; 

      return View(); 
    } 
}} 

Answer 2

、次のようにループのためのあなたの2を置き換える：

//Create list of startdates that are greater than any of the end dates 
//and return the differences in days 
var list = from s in startDate 
      from e in endDate 
      where s > e 
      select (s-e).Days; 

//If any were found, take out the min of those 
int dhiraj = list.Count() == 0 ? 0 : list.Min(); 
//Update total 
total -= dhiraj;