あるアレイの値を別のアレイに追加する方法は？

Question

私は1つが完了していたから、二つの配列を持つ他：

let result = [ 
    Score(name: "Steven", isComplete: true, finalScore: 12), 
    Score(name: "Helen", isComplete: true, finalScore: 12), 
    Score(name: "Adalbert", isComplete: false, finalScore: 12), 
    Score(name: "Christian", isComplete: false, finalScore: 12), 
    Score(name: "Susan", isComplete: false, finalScore: 3), 
    Score(name: "Julia", isComplete: false, finalScore: 13), 
    Score(name: "Robert", isComplete: false, finalScore: 13), 
    Score(name: "Mercedes", isComplete: false, finalScore: 2), 
    Score(name: "Gwendolin", isComplete: true, finalScore: 2), 
] 

：私は結果はこのように見えるような方法で第二の値を持つ最初の配列を完了できるか

struct Score { 
    let name: String 
    let isComplete: Bool 
    let finalScore: Int 
} 

var scores = [ 
    Score(name: "Steven", isComplete: false, finalScore: 12), 
    Score(name: "Helen", isComplete: false, finalScore: 12), 
    Score(name: "Adalbert", isComplete: false, finalScore: 12), 
    Score(name: "Christian", isComplete: false, finalScore: 12), 
    Score(name: "Susan", isComplete: false, finalScore: 3), 
    Score(name: "Julia", isComplete: false, finalScore: 13), 
    Score(name: "Robert", isComplete: false, finalScore: 13), 
    Score(name: "Mercedes", isComplete: false, finalScore: 2), 
    Score(name: "Gwendolin", isComplete: false, finalScore: 2), 
] 



struct Complete { 
    let name: String 
    let isComplete: Bool 
} 

var complete = [ 
    Complete(name: "Steven", isComplete: true), 
    Complete(name: "Helen", isComplete: true), 
    Complete(name: "Mercedes", isComplete: false), 
    Complete(name: "Gwendolin", isComplete: true), 
    // Name doesn´t exist in `score` and shouldn´t show up in the result: 
    Complete(name: "nonexistingName", isComplete: true) 
] 

通常、私は自分の試行の草稿を投稿しますが、私は非常に速いので、私は分かりません。アドバイスありがとう。

Answer 1

は最終的に、あなたはおそらく、「プレイヤー」モデルのいくつかの並べ替えで、おそらく、あなたのモデルを再考すべきです。

struct Score { 
    let name: String 
    var isComplete: Bool 
    let finalScore: Int 
} 

struct Complete { 
    let name: String 
    let isComplete: Bool 
} 

var scoresDictionary: [String : Score] = [:] 

// this populates scoresDictionary with your array, keyed with the names 
[ Score(name: "Steven", isComplete: false, finalScore: 12), 
    Score(name: "Helen", isComplete: false, finalScore: 12), 
    Score(name: "Adalbert", isComplete: false, finalScore: 12), 
    Score(name: "Christian", isComplete: false, finalScore: 12), 
    Score(name: "Susan", isComplete: false, finalScore: 3), 
    Score(name: "Julia", isComplete: false, finalScore: 13), 
    Score(name: "Robert", isComplete: false, finalScore: 13), 
    Score(name: "Mercedes", isComplete: false, finalScore: 2), 
    Score(name: "Gwendolin", isComplete: false, finalScore: 2), 
    ].forEach { scoresDictionary[$0.name] = $0} 

let complete = [ 
    Complete(name: "Steven", isComplete: true), 
    Complete(name: "Helen", isComplete: true), 
    Complete(name: "Mercedes", isComplete: false), 
    Complete(name: "Gwendolin", isComplete: true), 
    // Name doesn´t exist in `score` and shouldn´t show up in the result: 
    Complete(name: "nonexistingName", isComplete: true) 
] 

//Updates only the found values in scoresDictionary 
complete.forEach { scoresDictionary[$0.name]?.isComplete = $0.isComplete } 

// The dictionary is updated, but in case you just want the Scores, this gives you an array 
let result: [Score] = Array(scoresDictionary.values) 

Answer 2

基本的にはscoresを繰り返し、一致するものを探すのはCompleteです。見つけた場合は、isCompleteをtrueまたはfalseに設定してScoreを返します。見つからない場合は、元のScoreをそのまま返します。

var final: [Score] = scores.map { aScore in 

    let comp = complete.first { aScore.name == $0.name } 
    if let comp = comp { 
     return Score(name: aScore.name, isComplete: comp.isComplete || aScore.isComplete, finalScore: aScore.finalScore) 
    } 
    return aScore 
} 

final.forEach { 
    print($0.name, $0.isComplete, $0.finalScore) 
} 

プリント：あなたは、切断のこの種を持っていないので、

Steven true 12 
Helen true 12 
Adalbert false 12 
Christian false 12 
Susan false 3 
Julia false 13 
Robert false 13 
Mercedes false 2 
Gwendolin true 2