PHPでJSONデータの変数を読み込んで保存する

Question

次のJSONデータはID番号があります。最後に：何ができるかように$ johnemail ==「John@bar.com」

、ジョンの変数$ johnemailに格納します。

[{"Name":"malek","Email":"malek@bar.com","Donation":"5","Type":"Cash","id":0},{"Name":"donnie","Email":"donnie@bar.com","Donation":"6","Type":"Cheque","id":1},{"Name":"ramanuj","Email":"ramanuj@bar.com","Donation":"3","Type":"NEFT","id":2},{"Name":"neha","Email":"neha@bar.com","Donation":"2","Type":"RTGS","id":3},{"Name":"aasha","Email":"aasha@bar.com","Donation":"1","Type":"CC","id":4},{"Name":"zia","Email":"zia@bar.com","Donation":"6","Type":"PayU","id":5},{"Name":"John","Email":"John@bar.com","Donation":"7","Type":"Instamojo","id":6}] 

私は、特に電子メールを取得したいですそれを行う最も簡単な方法は？

Answer 1

使用した簡単な解決策json_decode、およびarray_search機能（PHP 5.5以降で利用可能）array_column：

$json_data = '[{"Name":"malek","Email":"malek@bar.com","Donation":"5","Type":"Cash","id":0},{"Name":"donnie","Email":"donnie@bar.com","Donation":"6","Type":"Cheque","id":1},{"Name":"ramanuj","Email":"ramanuj@bar.com","Donation":"3","Type":"NEFT","id":2},{"Name":"neha","Email":"neha@bar.com","Donation":"2","Type":"RTGS","id":3},{"Name":"aasha","Email":"aasha@bar.com","Donation":"1","Type":"CC","id":4},{"Name":"zia","Email":"zia@bar.com","Donation":"6","Type":"PayU","id":5},{"Name":"John","Email":"John@bar.com","Donation":"7","Type":"Instamojo","id":6}]'; 

$search_name = 'John'; 
$items = json_decode($json_data, TRUE); 
$emails = array_column($items, 'Name', 'Email'); // email is good for using as array key, as it should be unique 
$johnemail = array_search($search_name, $emails); // note that this is case-sensitive search 

print_r($johnemail); // "John@bar.com"