XMLをオブジェクトに逆シリアル化する方法

Question

このコードを実行していますが、xmlデータにアクセスできません。私はC＃でクラスへとオブジェクトには、次のXMLシリアル化を解除したい

：

XMLファイルはです：

<EmployeeCollection> 
    <EmployeeDetail> 
    <Employee ID ="EMP-01"> 
     <Name>ABC</Name> 
     <MobileNumber></MobileNumber> 
     <Age>20</Age> 
     <Gender>Male</Gender> 
     <MartialStatus>Single</MartialStatus> 
     <DOB>1997-01-12</DOB> 
     <Branch Name="XYZ"> 
      <CountryCode>IND</CountryCode> 
      <EstablishmentDate>2013-01-15</EstablishmentDate> 
     </Branch> 
    </Employee> 
    <Employee ID ="EMP-02"> 
     <Name>DEF</Name> 
     <MobileNumber>9685741236</MobileNumber> 
     <Age>19</Age> 
     <Gender>Male</Gender> 
     <MartialStatus>Single</MartialStatus> 
     <DOB>19998-12-21</DOB> 
     <Branch Name="PQR"> 
      <CountryCode>US</CountryCode> 
      <EstablishmentDate>2011-01-23</EstablishmentDate> 
     </Branch> 
    </Employee> 
    </EmployeeDetail> 
</EmployeeCollection> 

私はこの持っている：

public class Employee 
{ 
    [XmlAttribute("ID")] 
    public string ID    { get; set; } 

    [XmlElement("Name")] 
    public string Name    { get; set; } 

    [XmlElement("MobileNumber")] 
    public long MobileNumber  { get; set; } 

    [XmlElement("Age")] 
    public int Age     { get; set; } 

    [XmlElement("Gender")] 
    public string Gender   { get; set; } 

    [XmlElement("MartialStatus")] 
    public string MartialStatus  { get; set; } 

    [XmlElement("DOB")] 
    public DateTime DOB     { get; set; } 

    [XmlArray("Branch")] 
    public BranchDetail[] Branch { get; set; } 
} 

public class BranchDetail 
{ 
    [XmlAttribute("Name")] 
    public string BranchName  { get; set; } 

    [XmlElement("CountryCode")] 
    public string CountryCode  { get; set; } 

    [XmlElement("EstablishmentDate")] 
    public DateTime EstablishmentDate { get; set; } 
} 

[XmlRoot("EmployeeDetail")] 
public class EmployeeCollection 
{ 
    [XmlArray("Employee")] 
    public Employee[] Employee  { get; set; } 
} 

を私のコードはです：

public class EmployeeSerializer 
{ 
    public void Deserialize() 
    { 
     EmployeeCollection Employees = null; 

     XmlSerializer serializer = new XmlSerializer(typeof(EmployeeCollection)); 

     StreamReader reader = new StreamReader(employee.xml); 

     Employees = (EmployeeCollection)serializer.Deserialize(reader); 

     reader.Close(); 

    } 
} 

オブジェクトにすべてのxmlデータを保存したいとします。

XMLデータにアクセスしようとしましたが、アクセスできませんでした。

Answer 1

あなたはあなただけのXmlElementAttributeを使用cuold、XmlArrayはここ属性の必要はありません。

[XmlRoot("EmployeeDetail")] 
public class EmployeeCollection 
{ 
    [XmlElementAttribute("Employee")] 
    public Employee[] Employee { get; set; } 
} 

と分岐プロパティから同じこと：

[XmlElementAttribute("Branch")] 
public BranchDetail[] Branch { get; set; } 

あなたは関数を使用する "貼り付け" の可能性あなたのXMLのためのC＃のコードを生成するVisual Studio。

Answer 2

まず、あなたはこの1のようないくつかのオンラインツールを使用することができます。

http://www.freeformatter.com/xsd-generator.html

次に、あなたがすべての種類をカスタマイズすることができXSDを取得：

次の更新

<xs:schema attributeFormDefault="unqualified" elementFormDefault="qualified" xmlns:xs="http://www.w3.org/2001/XMLSchema"> 
<xs:element name="EmployeeDetail"> 
    <xs:complexType> 
     <xs:sequence> 
      <xs:element name="Employee" maxOccurs="unbounded" minOccurs="0"> 
       <xs:complexType> 
        <xs:sequence> 
         <xs:element type="xs:string" name="Name"/> 
         <xs:element type="xs:long" name="MobileNumber"/> 
         <xs:element type="xs:byte" name="Age"/> 
         <xs:element type="xs:string" name="Gender"/> 
         <xs:element type="xs:string" name="MartialStatus"/> 
         <xs:element type="xs:date" name="DOB"/> 
         <xs:element name="Branch"> 
          <xs:complexType> 
           <xs:sequence> 
            <xs:element type="xs:string" name="CountryCode"/> 
            <xs:element type="xs:date" name="EstablishmentDate"/> 
           </xs:sequence> 
           <xs:attribute type="xs:string" name="Name" use="optional"/> 
          </xs:complexType> 
         </xs:element> 
        </xs:sequence> 
        <xs:attribute type="xs:string" name="ID" use="optional"/> 
       </xs:complexType> 
      </xs:element> 
     </xs:sequence> 
    </xs:complexType> 
</xs:element> 

あなたの変更：

ここだけです年齢はそれほど高くすることができないにもかかわらず、INT：：XSにバイトを：XSからAgeフィールドを変更する必要が

      <xs:element type="xs:int" name="Age"/> 

次にあなたが開発者プロンプトを開き、マイクロソフトからXsd.exeではツールを使用して、あなたのことができますC＃クラスを取得します：ここで

xsd.exe /c Test.xsd 

は結果である：

//------------------------------------------------------------------------------ 
// <auto-generated> 
//  This code was generated by a tool. 
//  Runtime Version:4.0.30319.42000 
// 
//  Changes to this file may cause incorrect behavior and will be lost if 
//  the code is regenerated. 
// </auto-generated> 
//------------------------------------------------------------------------------ 

using System.Xml.Serialization; 

// 
// This source code was auto-generated by xsd, Version=4.0.30319.17929. 
// 


/// <remarks/> 
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.0.30319.17929")] 
[System.SerializableAttribute()] 
[System.Diagnostics.DebuggerStepThroughAttribute()] 
[System.ComponentModel.DesignerCategoryAttribute("code")] 
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true)] 
[System.Xml.Serialization.XmlRootAttribute(Namespace="", IsNullable=false)] 
public partial class EmployeeDetail { 

    private EmployeeDetailEmployee[] employeeField; 

    /// <remarks/> 
    [System.Xml.Serialization.XmlElementAttribute("Employee")] 
    public EmployeeDetailEmployee[] Employee { 
     get { 
      return this.employeeField; 
     } 
     set { 
      this.employeeField = value; 
     } 
    } 
} 

/// <remarks/> 
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.0.30319.17929")] 
[System.SerializableAttribute()] 
[System.Diagnostics.DebuggerStepThroughAttribute()] 
[System.ComponentModel.DesignerCategoryAttribute("code")] 
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true)] 
public partial class EmployeeDetailEmployee { 

    private string nameField; 

    private long mobileNumberField; 

    private int ageField; 

    private string genderField; 

    private string martialStatusField; 

    private System.DateTime dOBField; 

    private EmployeeDetailEmployeeBranch branchField; 

    private string idField; 

    /// <remarks/> 
    public string Name { 
     get { 
      return this.nameField; 
     } 
     set { 
      this.nameField = value; 
     } 
    } 

    /// <remarks/> 
    public long MobileNumber { 
     get { 
      return this.mobileNumberField; 
     } 
     set { 
      this.mobileNumberField = value; 
     } 
    } 

    /// <remarks/> 
    public int Age { 
     get { 
      return this.ageField; 
     } 
     set { 
      this.ageField = value; 
     } 
    } 

    /// <remarks/> 
    public string Gender { 
     get { 
      return this.genderField; 
     } 
     set { 
      this.genderField = value; 
     } 
    } 

    /// <remarks/> 
    public string MartialStatus { 
     get { 
      return this.martialStatusField; 
     } 
     set { 
      this.martialStatusField = value; 
     } 
    } 

    /// <remarks/> 
    [System.Xml.Serialization.XmlElementAttribute(DataType="date")] 
    public System.DateTime DOB { 
     get { 
      return this.dOBField; 
     } 
     set { 
      this.dOBField = value; 
     } 
    } 

    /// <remarks/> 
    public EmployeeDetailEmployeeBranch Branch { 
     get { 
      return this.branchField; 
     } 
     set { 
      this.branchField = value; 
     } 
    } 

    /// <remarks/> 
    [System.Xml.Serialization.XmlAttributeAttribute()] 
    public string ID { 
     get { 
      return this.idField; 
     } 
     set { 
      this.idField = value; 
     } 
    } 
} 

/// <remarks/> 
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.0.30319.17929")] 
[System.SerializableAttribute()] 
[System.Diagnostics.DebuggerStepThroughAttribute()] 
[System.ComponentModel.DesignerCategoryAttribute("code")] 
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true)] 
public partial class EmployeeDetailEmployeeBranch { 

    private string countryCodeField; 

    private System.DateTime establishmentDateField; 

    private string nameField; 

    /// <remarks/> 
    public string CountryCode { 
     get { 
      return this.countryCodeField; 
     } 
     set { 
      this.countryCodeField = value; 
     } 
    } 

    /// <remarks/> 
    [System.Xml.Serialization.XmlElementAttribute(DataType="date")] 
    public System.DateTime EstablishmentDate { 
     get { 
      return this.establishmentDateField; 
     } 
     set { 
      this.establishmentDateField = value; 
     } 
    } 

    /// <remarks/> 
    [System.Xml.Serialization.XmlAttributeAttribute()] 
    public string Name { 
     get { 
      return this.nameField; 
     } 
     set { 
      this.nameField = value; 
     } 
    } 
}