イムを必要としながら、「TypeError例外を:ほとんど1つの引数で予想される入力、19だ」 のpythonへイムちょっと新しい、そうすることができますが誰かが初心者のように私に説明するのを助ける?ループは1つの引数を期待しますが、私のドラッグレースシムのアップグレードストアを作成しようとしているが、それは言い続け、より
upgradeQ=input("\nWould you like to purchase an upgrade? (y/n) ")
while upgradeQ=="y":
upgradeList=int(input("\n1. Engine ($1000)",userEngine,"/ 5",
"\n2. Spoiler ($250)",userSpoiler,"/ 6",
"\n3. Body ($750)",userBody,"/ 6",
"\n4. Wheels ($500)",userWheels,"/ 10",
"\n5. Exhaust ($250)",userExhaust,"/ 5",
"\n6. Transmission ($500)",userTrans,"/ 4",
"Which upgrade would you like to purchase? (1-6) "))
# Engine Upgrades
if upgradeList==1 and (bank-enginePrice)<0:
print("\nYou do not have sufficient funds!")
upgradeQ=input("\nWould you like to purchase an upgrade? (y/n) ")
elif upgradeList==1 and (userEngine>=6):
print("\nYou have the maximum upgrades for engine.")
upgradeQ=input("\nWould you like to purchase an upgrade? (y/n) ")
elif upgradeList==1 and (bank-enginePrice)>0:
bank-=enginePrice
userEngine+=1
print("\nSuccess! You have purchased the Engine upgrade.")
upgradeQ=input("\nWould you like to purchase an upgrade? (y/n) ")
「どのアップグレードあなたが購入したいですか?(1-6)」には、右upgradeListの最後の行にはTypeErrorを言う))
の任意の数を受け入れるよう印刷は例外です。 ** 1つの**文字列を渡します。 –
あなたは '入力()'は何を思いますか? –
どうすればいいですか? – Josh