私のプログラムはユーザに名前を尋ね、3つの乱数のシャッフルを要求します。基本的なJavaプログラムのチューンアップの手助け
シャッフルのいずれかが目的の数(31)に追加されると、シャッフルが停止します。私はプログラムが最後のシャッフルだけを読むということが必要です。例えば。あなたがしたいですかどのように多くのシャッフル
:あなたが勝者です3
10 + 11 + 10 = 31おめでとうを!
電流出力である:
9 + 6 + 8
8 + 10 + 12
7 + 9 + 11
私は支援が必要ユーザーが名前にアルファベット以外の文字を使用できないようにします。数字が印刷されるまでにユーザーが持っていたシャッフルの数を印刷する機能も必要です。ここで
は、最後のシャッフルが勝者か敗者として読み取る得ることができることを確認するために
`import java.util.InputMismatchException;
import java.util.Scanner;
import java.io.IOException;
import java.util.Random;
public class StringVariables {
public static void main(String[] args) throws NumberFormatException,
IOException {
// user inputs their name in this section
Scanner user_input = new Scanner(System.in);
//enter their first name
String first_name;
System.out.print("Enter Your First Name: ");
first_name = user_input.next();
//enter their last name
String last_name;
System.out.print("Enter Your Last Name: ");
last_name = user_input.next();
//full name printed together
String full_name;
full_name = first_name + " " + last_name;
System.out.println(full_name + " Is Now Playing");
// this is the shuffle portion as well as something to see if a number
int numShuffles = -1;
while (numShuffles < 0) {
System.out.println("How many times do you want the numbers shuffled? ");
try {
numShuffles = user_input.nextInt();
} catch (InputMismatchException inputException) {
System.out.print("Please enter a valid number. \n");
//this is the buffer that resets if the user types a letter instead of a number, or any other character
user_input.next();
}
}
// here is going to be the loop for shuffles
// we are now going to generate their random number and add a delay
// after completing their name fields
delay(3000);
System.out
.println(" You will be given a hand of 3 random numbers between 7-13"
+ "\n you will be drawn a the number of shuffles as you entered above ");
delay(2000);
System.out
.println(" Then, the computer will add the random numbers and if it is equal to 31, you win.");
/*
* end of explanation of the game, next i will create a new screen with
* the user's name and numbers
*/
delay(4000);
// printing 25 blank lines
for (int i = 0; i < 25; i++)
System.out.println(" ");
System.out.println("User playing: " + full_name);
System.out.println("Your lucky numbers are...");
// random number generator
Random random = new Random();
while (true) {
// the shuffle loop
boolean isWinner = false;
for (int i = 0; i < numShuffles; i++) {
int num1 = 7 + random.nextInt(7);
int num2 = 7 + random.nextInt(7);
int num3 = 7 + random.nextInt(7);
System.out.println(num1 + " + " + num2 + " + " + num3 + " = "
+ (num1 + num2 + num3));
// adding the numbers together
if (num1 + num2 + num3 == 31) {
isWinner = true;
System.out
.println("Congratulations !! You are the Lucky Winner !!!!");
break;
//if you loose every shuffle
}
}
if (!isWinner)
System.out.println("Better Luck Next Time");
// play again prompt
System.out
.println(" Do you want to play again? (If you do enter y or yes) \n To exit press any other key ");
String input = user_input.next();
if (!"y".equalsIgnoreCase(input) && !"yes".equalsIgnoreCase(input)) {
break;
}
}
// if pressed y or yes the program will run again with the same number of shuffles entered from before
user_input.close();
}
// delay field
public static void delay(int millis) {
try {
Thread.sleep(millis);
} catch (InterruptedException exp) {
// delay field
}
}
}`
重複している可能性があるので、シャッフルではありません。例えば7,7,7。 –
このプロジェクトで重複している数字は大丈夫です@PeterLawrey –
あなたが手助けできることは何ですか? –