SQL Server：すべての暦日の営業日

Question

次の表があります。カナダの日は7月1日で、私のデータソースは営業日のみです。 7月1日が私のソーステーブルであるTABLE_A（名前：conm）にはないことに注意してください。

CREATE TABLE [dbo].[comn] 
(
    CONM varchar(48), 
    valuedate datetime, 
    closeprice decimal(5,2) 
) 
GO 

INSERT INTO comn VALUES ('SAPUTO INC', '2016-06-27', 37.66); 
INSERT INTO comn VALUES ('SAPUTO INC', '2016-06-28', 38.34); 
INSERT INTO comn VALUES ('SAPUTO INC', '2016-06-29', 38.48); 
INSERT INTO comn VALUES ('SAPUTO INC', '2016-06-30', 38.37); 
INSERT INTO comn VALUES ('SAPUTO INC', '2016-07-04', 38.12); 
INSERT INTO comn VALUES ('SAPUTO INC', '2016-07-05', 38.59); 
INSERT INTO comn VALUES ('SAPUTO INC', '2016-07-06', 38.75); 
GO 

また、カナダの祝日はすべてTABLE_B（businessdaysCAN）です。

CREATE TABLE [dbo].[businessdaysCAN] 
(
    valuedate datetime, 
    isholidayCA decimal(5,2) 
) 
GO 

INSERT INTO businessdaysCAN VALUES ('2016-02-15',1); 
INSERT INTO businessdaysCAN VALUES ('2016-03-25', 1); 
INSERT INTO businessdaysCAN VALUES ('2016-05-23', 1); 
INSERT INTO businessdaysCAN VALUES ('2016-07-01', 1); 
INSERT INTO businessdaysCAN VALUES ('2016-08-01', 1); 
INSERT INTO businessdaysCAN VALUES ('2016-09-05', 1); 
INSERT INTO businessdaysCAN VALUES ('2016-10-10', 1); 
GO 

私は、このようなカナダの休日があった場合、私は前日の価格で私のファイナルテーブルでの休日の日付を持っているように、出力テーブルを持っていると思います。

CONM  valuedate    closeprice 
------------------------------------------------ 
SAPUTO INC 2016-06-27 00:00:00.000  37.66 
SAPUTO INC 2016-06-28 00:00:00.000  38.34 
SAPUTO INC 2016-06-29 00:00:00.000  38.48 
SAPUTO INC 2016-06-30 00:00:00.000  38.37 
SAPUTO INC 2016-07-04 00:00:00.000  38.12 
SAPUTO INC 2016-07-05 00:00:00.000  38.59 
SAPUTO INC 2016-07-06 00:00:00.000  38.75 

Answer 1

あなたは

DECLARE @comn table (conm varchar(10) , valueDate date, closePrice decimal(10,2)); 
DECLARE @businessdaysCAN table(calDate date, isHolidayCA bit); 

INSERT @comn (conm,valueDate,closePrice) VALUES 
('SAPUTO INC','2016-06-27',37.66) 
,('SAPUTO INC','2016-06-28',38.34) 
,('SAPUTO INC','2016-06-29',38.48) 
,('SAPUTO INC','2016-06-30',38.37) 
,('SAPUTO INC','2016-07-04',38.12) 
,('SAPUTO INC','2016-07-05',38.59) 
,('SAPUTO INC','2016-07-06',38.75); 

INSERT @businessdaysCAN (calDate, isHolidayCA) VALUES 
('2016-05-23',1) 
,('2016-07-01',1) 
,('2016-08-01',1); 

WITH 
cteMinMaxDates as 
(
select 
conm 
,Min(valueDate) as startdate 
,Max(valueDate) as enddate 
from @comn 
Group by conm 
), 
cteAllDates 
    AS (SELECT conm 
       ,startdate 
       ,enddate 
       ,valueDate = (SELECT valueDate FROM @comn a where a.valueDate = t.startdate and a.conm = t.conm) 
     FROM cteMinMaxDates t 
     UNION ALL 
     SELECT conm 
       ,Dateadd(day, 1, startdate) startdate 
       ,enddate 
       ,valueDate = CASE WHEN (SELECT valueDate FROM @comn a where a.valueDate = startdate and a.conm = conm) IS NULL THEN valueDate ELSE (SELECT valueDate FROM @comn a where a.valueDate = startdate and a.conm = conm) END 
     FROM cteAllDates 
     WHERE startdate < enddate) 
SELECT 
    D.conm 
    ,D.startdate valuedate 
    ,IsNull(A.closePrice , B.closePrice) closePrice 
FROM cteAllDates D 
     LEFT JOIN @comn A 
       ON D.conm = A.conm 
       AND D.startdate = A.valuedate 
     LEFT JOIN @comn B 
       ON D.valuedate = B.valuedate 
WHERE A.valuedate IS NOT NULL 
     OR EXISTS (SELECT 1 FROM @businessdaysCAN c where d.startdate = c.calDate) 

結果

conm  valuedate closePrice 
---------- ---------- --------------------------------------- 
SAPUTO INC 2016-06-27 37.66 
SAPUTO INC 2016-06-28 38.34 
SAPUTO INC 2016-06-29 38.48 
SAPUTO INC 2016-06-30 38.37 
SAPUTO INC 2016-07-01 38.37 
SAPUTO INC 2016-07-04 38.12 
SAPUTO INC 2016-07-05 38.59 
SAPUTO INC 2016-07-06 38.75 

それを試すことができます範囲内のすべての日付が必要です

WHERE A.valuedate IS NOT NULL 
     OR EXISTS (SELECT 1 FROM @table_b c where d.startdate = c.calDate) 

あなたのデータの写真を投稿

結果

conm  valuedate closePrice 
---------- ---------- --------------------------------------- 
SAPUTO INC 2016-06-27 37.66 
SAPUTO INC 2016-06-28 38.34 
SAPUTO INC 2016-06-29 38.48 
SAPUTO INC 2016-06-30 38.37 
SAPUTO INC 2016-07-01 38.37 
SAPUTO INC 2016-07-02 38.37 
SAPUTO INC 2016-07-03 38.37 
SAPUTO INC 2016-07-04 38.12 
SAPUTO INC 2016-07-05 38.59 
SAPUTO INC 2016-07-06 38.75 

Answer 2

これは、あなたが長いか短い範囲が必要な場合は、追加の「PASSを追加する必要があり長い場合だけ（コード内の日付を変更、2000年1月1日以来、あなたのすべての日付のテーブルを与えるだろう"CTEでは65kです。場合は、その後、LEFT JOINかRIGHT JOINこれはあなたのテーブルにすることができますし、あなたがnullであるところ、このからの値を使用して...

WITH 
    _PASS0 AS (SELECT 1 AS Num UNION ALL SELECT 1),   --2 ROWS 
    _PASS1 AS (SELECT 1 AS Num FROM _PASS0 AS A, _PASS0 AS B), --4 ROWS 
    _PASS2 AS (SELECT 1 AS Num FROM _PASS1 AS A, _PASS1 AS B), --16 ROWS 
    _PASS3 AS (SELECT 1 AS Num FROM _PASS2 AS A, _PASS2 AS B), --256 ROWS 
    _PASS4 AS (SELECT 1 AS Num FROM _PASS3 AS A, _PASS3 AS B), --65,536 ROWS 
    _TALLY AS (SELECT 0 AS Number UNION ALL SELECT ROW_NUMBER() OVER(ORDER BY Num) AS Number FROM _PASS4) 

SELECT dateadd(DAY,Number,'20000101') AS CalendarDate 
FROM _Tally 
WHERE Number <= datediff(DAY,'20000101',getdate());