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モジュールソケットを持つ簡単なクライアント/サーバープログラムを作成しようとしていました。すべての標準ソケット実装の基本的なチュートリアルです。socket.accept()無効な引数
#Some Error in sock.accept (line 13) --> no fix yet
import socket
import sys
serversocket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
host = socket.gethostname()
print >>sys.stderr, 'starting up on %s' % host
serversocket.bind((host, 9999))
serversocket.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
#listening for incoming connections
while True:
# Wait for a connection
print >>sys.stderr, 'waiting for a connection'
connection , client_address = serversocket.accept()
try:
print >>sys.stderr, 'connection from', client_address
#Receive data in small chunks and retransmit it
while True:
data = connection.recv(16)
print >>sys.stderr,'received "%s"' % data
if data:
print >>sys.stderr, 'sending data back to the client'
connection.sendall(data)
else:
print >>sys.stderr, 'no more data from', client_address
break
finally:
#Clean up the connection
#Will be executed everytime
connection.close()
ことができます出力は
C:\Python27\python27.exe C:/Users/Marcel/Desktop/Projekte/Python/Sockets/Socket_Test/server.py
starting up on Marcel-HP
waiting for a connection
Traceback (most recent call last):
File "C:/Users/Marcel/Desktop/Projekte/Python/Sockets/Socket_Test/server.py", line 16, in <module>
connection , client_address = serversocket.accept()
File "C:\Python27\lib\socket.py", line 206, in accept
sock, addr = self._sock.accept()
socket.error: [Errno 10022] Ein ung�ltiges Argument wurde angegeben