selectタグからデータベースへの値の取得方法

Question

フォームをデータベースに投稿できますが、selectタグの値として0しか得られません。データベースの各選択オプションの値を取得するにはどうすればよいですか？

<select class="span6" name="test_name"> 
<?php 
include ('include/connect.php'); 

$query1 = "SELECT test_name FROM mst_test ORDER BY test_name ASC"; 
$result = mysql_query($query1); 

while(list($test_name)=mysql_fetch_array($result)) 
{ 
    echo "<option value ='$test_name' selected>$test_name</option>"; 
} 
?> 
</select> 

Answer 1

<select class="span6" name="test_name"> 
    <?php 
    include ('include/connect.php'); 
    $query1 = "SELECT test_name FROM mst_test ORDER BY test_name ASC"; 
    $result = mysql_query($query1); 
    while ($row = mysql_fetch_array($result)) {?> 
    <option value ="<?php echo $row['test_name'];?>"><?php echo $row['test_name'];?></option> 
    <?php }?> 
</select> 

NOTE: [The mysql extension is deprecated and will be removed in the future: use mysqli or PDO instead ]

Answer 2

<select class="span6" name="test_name"> 
<option value="">Please select</option> 
    <?php 
    include ('include/connect.php'); 
    $query1 = "SELECT test_name FROM mst_test ORDER BY test_name ASC"; 
    $result = mysql_query($query1); 
    while ($test_name = mysql_fetch_assoc($result)) { 

    echo "<option value='{$test_name['test_name']}'>{$test_name['test_name']}</option>"; 
    } 
    ?> 
</select> 

私は強くあなたが `するmysql_query（）は`最新のPHPのバージョンから廃止されましたMySQLiまたはPDO