のMySQL - 次のデータを使用して、各データグループの見返り最後のレコード

Question

...

+--------------+--------+---------------+-----------------+----------------+ 
| EQUIPMENT_ID | CML_ID | INSPECTION_NO | INSPECTION_DATE | WALL_THICKNESS | 
+--------------+--------+---------------+-----------------+----------------+ 
| B1000-V001 | 1  | 1    | 1/01/2016  | 10    | 
| B1000-V001 | 1  | 2    | 2/01/2016  | 9    | 
| B1000-V001 | 1  | 3    | 3/01/2016  | 3    | 
| B1000-V001 | 1  | 4    | 4/01/2016  | 7    | 
| B1000-V001 | 1  | 5    | 5/01/2016  | 5    | 
| B1000-V001 | 1  | 6    | 6/01/2016  | 4    | 
| B1000-V001 | 1  | 7    | 7/01/2016  | 4    | 
| B1000-V001 | 1  | 8    | 8/01/2016  | 8    | 
| B1000-V001 | 1  | 9    | 9/01/2016  | 17    | 
| B1000-V001 | 1  | 10   | 10/01/2016  | 5    | 
| B1000-X123 | 5  | 1    | 1/01/2016  | 2    | 
| B1000-X123 | 5  | 2    | 2/01/2016  | 8    | 
| B1000-X123 | 5  | 3    | 3/01/2016  | 4    | 
| B1000-X123 | 5  | 4    | 4/01/2016  | 5    | 
| B1000-X123 | 5  | 5    | 5/01/2016  | 7    | 
| B1000-P789 | 3  | 1    | 1/01/2016  | 8    | 
| B1000-P789 | 3  | 2    | 2/01/2016  | 7    | 
| B1000-P789 | 3  | 3    | 3/01/2016  | 5    | 
| B1000-P789 | 3  | 4    | 4/01/2016  | 1    | 
| B1000-P789 | 3  | 5    | 5/01/2016  | 4    | 
+--------------+--------+---------------+-----------------+----------------+ 

私は、次の結果を生成するための最速の方法をしたい...

+--------------+--------+---------------+-----------------+----------------+ 
| EQUIPMENT_ID | CML_ID | INSPECTION_NO | INSPECTION_DATE | WALL_THICKNESS | 
| B1000-V001 | 1  | 10   | 10/01/2016  | 5    | 
| B1000-P789 | 3  | 5    | 5/01/2016  | 4    | 
| B1000-X123 | 5  | 5    | 5/01/2016  | 7    | 
+--------------+--------+---------------+-----------------+----------------+ 

すなわちGROUP BY EQUIPMENT_ID 、CML_IDを返し、常に最大検査番号に関連付けられたレコードを返します。

Answer 1

以下のクエリを試してください。

Select a.Equipment_ID, a.CML_ID, b.INSPECTION_NO,a.INSPECTION_DATE, a.WALL_THICKNESS 
    from 
    #YourTable a inner join 
    (
    Select Equipment_ID, CML_ID, max(INSPECTION_NO)as INSPECTION_NO 
    from #YourTable 
    Group By Equipment_ID,CML_ID 
    ) b 
    on a.Equipment_ID=b.Equipment_ID and a.CML_ID=b.CML_ID and a.INSPECTION_NO=b.INSPECTION_NO 
    order by a.Equipment_ID 

SQL_FIDDLE：DEMO

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