お問い合わせフォームにエラーがあり、アクションPHPスクリプトを起動しません

Question

私はこの質問に既に回答している可能性があることを知っていますが、私が得た特定のケースを見つけることはできません。

だから、私のコンタクトフォームは次のようになります。

<div id="contact-form"> 
    <div id="message"></div> 
    <form method="POST" action="php/contact.php" name="contactform" id="contactform"> 
     <input name="name" type="text" id="name" class="inputForm2" onclick="this.select()" value="Name"> 
     <input name="email" type="text" id="email" onclick="this.select()" value="E-mail"> 
     <textarea name="comments" id="comments" onclick="this.select()">Message</textarea> 
     <input type="submit" class="send_message transition" id="submit" value="Send Message"> 
    </form> 
</div> 

とPHPスクリプト

function isEmail($email) { Skipped this one to save space } 

if (!defined("PHP_EOL")) define("PHP_EOL", "\r\n"); 

$name  = $_POST['name']; 
$email = $_POST['email']; 
$content = $_POST['comments']; 


if(trim($name) == '') { 
    echo '<div class="error_message">Enter your name.</div>'; 
    exit(); 
} else if(trim($email) == '') { 
    echo '<div class="error_message">Enter a valid email address.</div>'; 
    exit(); 
} else if(!isEmail($email)) { 
    echo '<div class="error_message">You have enter an invalid e-mail address, try again.</div>'; 
    exit(); 
} else if(trim($content) == '') { 
    echo '<div class="error_message">Enter your message.</div>'; 
    exit(); 
} 

if(get_magic_quotes_gpc()) { 
    $comments = stripslashes($comments); 
} 

$emailTo = "x@y"; 

$subject = 'Youve been contacted by ' . $name . '.'; 

$e_body = "You have been contacted by: $name" . PHP_EOL . PHP_EOL; 
$e_reply = "E-mail: $email\r\nPhone: $phone"; 
$e_content = "Message:\r\n$comments" . PHP_EOL . PHP_EOL; 

//$content = wordwrap($e_body . $e_content . $e_reply, 70); 

$headers = "From: $email" . PHP_EOL; 
$headers .= "Reply-To: $email" . PHP_EOL; 
$headers .= "MIME-Version: 1.0" . PHP_EOL; 
$headers .= "Content-type: text/plain; charset=utf-8" . PHP_EOL; 
$headers .= "Content-Transfer-Encoding: quoted-printable" . PHP_EOL; 

if(mail($emailTo, $subject, $content, $headers)) { 

    echo "<fieldset>"; 
    echo "<div id='success_page'>"; 
    echo "<h3>Email Sent Successfully.</h3>"; 
    echo "<p>Thank you <strong>$name</strong>, your message has been submitted to us.</p>"; 
    echo "</div>"; 
    echo "</fieldset>"; 

} else { 

    echo 'ERROR!'; 
} 

あなたはこれで間違っているものを私を指してもらえますか？

Answer 1

まずあなたがPHPフォルダにcontact.phpを持っていることを確認し、またあなたのHTMLフォームが

その後、PHPに達している.IF私はあなたのhtml形式でonclickの方法を見ることができるので、あなたのHTMLフォームがPHPコードに達しているかどうか確認してくださいあなたが isemail機能を使用している.IF

あなたは、あなたはあなたが

function isEmail($email) { 

    return filter_var($email, FILTER_VALIDATE_EMAIL); 
    } 

完全なコード次のように更新してください検証にelse if(!isEmail($email)) {をチェックしているので、trueを返す必要はありisEmail($email)機能に問題がある

function isEmail($email) { 

     return filter_var($email, FILTER_VALIDATE_EMAIL); 
     } 

if (!defined("PHP_EOL")) define("PHP_EOL", "\r\n"); 

$name  = $_POST['name']; 
$email = $_POST['email']; 
$content = $_POST['comments']; 


if(trim($name) == '') { 
    echo '<div class="error_message">Enter your name.</div>'; 
    exit(); 
} else if(trim($email) == '') { 
    echo '<div class="error_message">Enter a valid email address.</div>'; 
    exit(); 
} else if(!isEmail($email)) { 
    echo '<div class="error_message">You have enter an invalid e-mail address, try again.</div>'; 
    exit(); 
} else if(trim($content) == '') { 
    echo '<div class="error_message">Enter your message.</div>'; 
    exit(); 
} 

if(get_magic_quotes_gpc()) { 
    $comments = stripslashes($comments); 
} 

$emailTo = "e.lucinskas@hotmail.co.uk"; 

$subject = 'Youve been contacted by ' . $name . '.'; 

$e_body = "You have been contacted by: $name" . PHP_EOL . PHP_EOL; 
$e_reply = "E-mail: $email\r\nPhone: $phone"; 
$e_content = "Message:\r\n$comments" . PHP_EOL . PHP_EOL; 

//$content = wordwrap($e_body . $e_content . $e_reply, 70); 

$headers = "From: $email" . PHP_EOL; 
$headers .= "Reply-To: $email" . PHP_EOL; 
$headers .= "MIME-Version: 1.0" . PHP_EOL; 
$headers .= "Content-type: text/plain; charset=utf-8" . PHP_EOL; 
$headers .= "Content-Transfer-Encoding: quoted-printable" . PHP_EOL; 

if(mail($emailTo, $subject, $content, $headers)) { 

    echo "<fieldset>"; 
    echo "<div id='success_page'>"; 
    echo "<h3>Email Sent Successfully.</h3>"; 
    echo "<p>Thank you <strong>$name</strong>, your message has been submitted to us.</p>"; 
    echo "</div>"; 
    echo "</fieldset>"; 

} else { 

    echo 'ERROR!'; 
}