複数の内部結合を含むJPAカスタムクエリ

Question

私は春のブートに慣れていないので、複数の内部結合を持つカスタムJPAクエリのヘルプが必要です。基本的に私はJPAクエリに次のSQLクエリを変換する必要があります。以下は

SELECT count(uc.certifications_groups) 
    FROM firms f 
    INNER JOIN firms_users_map fum on fum.firm_realm_id = f.firm_realm_id 
    INNER JOIN users u on u.global_auth_id = fum.global_auth_id 
    INNER JOIN users_certifications uc on uc.global_auth_id = u.global_auth_id 
    WHERE f.firm_realm_id = 1 and uc.certifications_groups = 'qbo' 
    GROUP BY uc.certifications_groups; 

は、コードの構造です：

@Entity(name = "firms") 
@Table(name = "firms") 
public class FirmEntity { 

    @Id 
    private long firmRealmId; 

    @JoinColumn(name = "tier_name", nullable = false) 
    private String tierName; 

    @Column(nullable = false) 
    private int currentPoints; 

    @Column(nullable = true) 
    private Date gracePeriodEnd; 

    @ManyToMany 
    @JoinTable(
     name = "firms_users_map", 
     inverseJoinColumns = { @JoinColumn(name = "global_auth_id") }, 
     joinColumns = { @JoinColumn(name = "firm_realm_id") } 
    ) 
    private Set<UserEntity> users; 

    public Set<UserEntity> getUsers() { 
     return users; 
    } 

    public void setUsers(Set<UserEntity> users) { 
     this.users = users; 
    } 

    @Entity 
    @Table(name = "users") 
    public class UserEntity { 

    @Id 
    @Column(name="global_auth_id", nullable = false) 
    private long global_auth_id; 


    public long getGlobal_auth_id() { 
     return global_auth_id; 
    } 

    public void setGlobal_auth_id(long global_auth_id) { 
     this.global_auth_id = global_auth_id; 
    } 

    @OneToMany 
    @JoinTable(
     name = "user_certifications", 
     inverseJoinColumns = { @JoinColumn(name = "certification_group") }, 
     joinColumns = {@JoinColumn(name="global_auth_id")} 
    ) 
    private Set<users_certificationsEntity> users_certificationsEntity; 


    public Set<users_certificationsEntity> getUser_certifications() { 
     return users_certificationsEntity; 
    } 

    public void setUser_certifications(Set<users_certificationsEntity> user_certifications) { 
     this.users_certificationsEntity = user_certifications; 
    } 

FirmRepository

FirmEntity

public interface FirmRepository extends CrudRepository<FirmEntity, Long> { 


@Query("select count(c) from firms f inner join f.users c inner join 
c.users_certificationsEntity x where f.firmRealmId = ?1 " 
     + "and x.certifications_groups=qbo_adv") 
int count_qbo_adv_Certification(long firmRealmId) 

CertificationCountSignalImpl

public class CertificationCountSignalImpl implements Signal { 

    @Autowired 
    private FirmRepository firmRepository; 

    @Autowired 
    private SignalMetadataRepository signalMetadataRepository; 

    @Autowired 
    private CertificationCountSignalImpl certificationCountSignalImpl; 


    private int get_qbo_certificationPoints(long firmRealmId) { 
     if(firmRealmId <=0) { 
      throw new IllegalArgumentException(); 
     } 
     int clientCount = firmRepository.countAllClients(firmRealmId); 

     int CertificationsCount_QBO_ByRealm_id = firmRepository.count_qbo_Certifications(firmRealmId); 

     int totalPoints =0; 
     int pointsCounter =0; 

Answer 1

あなたは、テーブル間の関係を宣言すると@query（例 - Construct JPA query for a OneToMany relation）内の単語をJOINを使用していないエンティティの構成を使用することができ、すべてのモミ、 またはクエリに参加使用ではなく、注釈@OneToManyはEntityクラス、例に - Hql, How to write join query between tables that has one to many relationship?

Answer 2

私は、次のJQLを使用して作業私のクエリを得た：

@Query("select count(c) " 
+   + "from firms f " 
+   + "inner join f.users u " 
+   + "inner join u.certifications c " 
+   + "where f.firmRealmId = ?1 " 
+   + "and c.certificationsGroups='qbo'") 
+ int count_qbo_Certifications (long firmRealmId);