最小金額から最大金額のグループを複数の列で作成する

Question

現在、私はMySQL 5.6.30を使用しています。ここで

名前がtemp_work

+----+-----------+----------+----------+--------+---------+-------+---------+ 
| id | client_id | account | category | t_year | t_month | t_day | amount | 
+----+-----------+----------+----------+--------+---------+-------+---------+ 
| 1 | 100  | Saving | deposit | 2016 | 12  | 14 | 100.84 | 
| 2 | 100  | Checking | withdraw | 2016 | 12  | 15 | 300.24 | 
| 3 | 100  | Checking | deposit | 2016 | 12  | 29 | 60.00 | 
| 4 | 101  | Saving | Withdraw | 2016 | 12  | 29 | 245.16 | 
| 5 | 100  | Saving | Withdraw | 2016 | 12  | 30 | 2200.00 | 
| 6 | 100  | Checking | Withdraw | 2016 | 12  | 30 | 2372.16 | 
| 7 | 100  | Saving | deposit | 2016 | 12  | 30 | 4327.00 | 
| 8 | 101  | Checking | Withdraw | 2017 | 1  | 3  | 80.00 | 
| 9 | 101  | Checking | Withdraw | 2017 | 1  | 3  | 1033.45 | 
| 10 | 100  | Saving | Withdraw | 2017 | 1  | 3  | 1339.16 | 
| 11 | 100  | Checking | deposit | 2017 | 1  | 4  | 140.00 | 
| 12 | 100  | Checking | Withdraw | 2017 | 1  | 4  | 216.73 | 
| 13 | 101  | Checking | Withdraw | 2017 | 1  | 4  | 1261.72 | 
+----+-----------+----------+----------+--------+---------+-------+---------+ 

であると私はclient_idの、アカウント、カテゴリ、t_year、t_monthによって最大量群への最低額からランクを必要とするテーブル内のデータがあります。

だから、これは私が期待したものであるか、類似した

+-----------+----------+----------+--------+---------+---------+------+ 
| client_id | account | category | t_year | t_month | amount | rank | 
+-----------+----------+----------+--------+---------+---------+------+ 
| 100  | Checking | deposit | 2016 | 12  | 60.00 | 1 | 
| 100  | Checking | deposit | 2017 | 1  | 140.00 | 1 | 
| 100  | Checking | withdraw | 2016 | 12  | 300.24 | 1 | 
| 100  | Checking | withdraw | 2016 | 12  | 2327.16 | 2 | 
| 100  | Checking | Withdraw | 2017 | 1  | 216.73 | 1 | 
| 100  | Saving | deposit | 2016 | 12  | 100.84 | 1 | 
| 100  | Saving | deposit | 2016 | 12  | 4327.00 | 2 | 
| 100  | Saving | Withdraw | 2016 | 12  | 2200.00 | 1 | 
| 100  | Saving | Withdraw | 2017 | 1  | 1339.16 | 1 | 
| 101  | Checking | Withdraw | 2017 | 1  | 80.00 | 1 | 
| 101  | Checking | Withdraw | 2017 | 1  | 1033.45 | 2 | 
| 101  | Checking | Withdraw | 2017 | 1  | 1261.72 | 3 | 
| 101  | Saving | Withdraw | 2016 | 12  | 245.16 | 1 | 
+-----------+----------+----------+--------+---------+---------+------+ 

ここでは私の最初の試みである：

Select 
tw1.client_id, tw1.account, tw1.category, tw1.t_year, tw1.t_month, tw1.amount 
,@rownum = case when @tmonth <> tw1.t_month then 0 else @rownum + 1 end as ranking 
,@tmonth := t_month as cmonth 
From 
(Select @rownum := 0 from dual) as r, 
(Select @tmonth := 0 from dual) as m, 
(Select client_id, account, category, t_year, t_month, amount 
    From  temp_work as tw 
    Order by client_id, account, category, t_year, t_month, amount) as tw1 

2回目の試行：

Select tw1.client_id, tw1.account, tw1.category, tw1.t_year, tw1.t_month, tw1.amount 
    ,@rownum = case when concat(@tyear, '-', @tmonth) <> concat(t_year, '-', t_month) then 0 else @rownum + 1 end as rank 
    ,@tyear := t_year as cyear 
    ,@tmonth := t_month as cmonth   
From 
(Select @rownum := 0) as r, 
(Select @tyear := 0) as y, 
(Select @tmonth := 0) as m, 
(
Select client_id, account, category, t_year, t_month, amount 
From temp_work 
Order by tw.client_id, tw.account, tw.category, t_year, t_month, tw.amount 
) as tw1 

しかし、上記のクエリは私に与えます以下のような同じ結果です。

+-----------+----------+----------+--------+---------+---------+------+ 
| client_id | account | category | t_year | t_month | amount | rank | 
+-----------+----------+----------+--------+---------+---------+------+ 
| 100  | Checking | deposit | 2016 | 12  | 60.00 | 1 | 
| 100  | Checking | deposit | 2017 | 1  | 140.00 | 1 | 
| 100  | Checking | withdraw | 2016 | 12  | 300.24 | 1 | 
| 100  | Checking | withdraw | 2016 | 12  | 2327.16 | 0 | 
| 100  | Checking | Withdraw | 2017 | 1  | 216.73 | 1 | 
| 100  | Saving | deposit | 2016 | 12  | 100.84 | 1 | 
| 100  | Saving | deposit | 2016 | 12  | 4327.00 | 0 | 
| 100  | Saving | Withdraw | 2016 | 12  | 2200.00 | 1 | 
| 100  | Saving | Withdraw | 2017 | 1  | 1339.16 | 1 | 
| 101  | Checking | Withdraw | 2017 | 1  | 80.00 | 1 | 
| 101  | Checking | Withdraw | 2017 | 1  | 1033.45 | 0 | 
| 101  | Checking | Withdraw | 2017 | 1  | 1261.72 | 0 | 
| 101  | Saving | Withdraw | 2016 | 12  | 245.16 | 1 | 
+-----------+----------+----------+--------+---------+---------+------+ 

この問題を解決するためのヒントを教えてください。

ありがとうございました。

Answer 1

ランク付けするための相関カウント集計のサブクエリを考えてみましょうは：

SELECT t.client_id, t.account, t.category, t.t_year, t.t_month, t.amount, 
     (SELECT COUNT(*) FROM temp_work sub 
     WHERE sub.amount <= t.amount 
     AND sub.client_id = t.client_id 
     AND sub.account = t.account 
     AND sub.t_year = t.t_year 
     AND sub.t_month = t.t_Month) AS rank 
FROM temp_work t 
ORDER BY t.client_id, t.account, t.category, t.t_year, t.t_month, t.amount 

Answer 2

「金額」に2番目の値を順番に並べ替えるように注文を並べ替えてみてください。これはあなたが望むものに近づけるでしょう。

Order by client_id, amount, account, category, t_year, t_month

あなたは、彼らがソートされた順序を決定するあなたの列をリストする順序。詳細情報については

：https://dev.mysql.com/doc/refman/5.7/en/sorting-rows.html