ない直接の1が、あなたは同じ効果を達成することができるようになりますRETURNING INTO
を使用して:
CREATE TABLE A(columnA VARCHAR2(10), columnB INT);
INSERT INTO A(columnA, columnB) VALUES ('Test', 10);
INSERT INTO A(columnA, columnB) VALUES ('Row 2', 20);
CREATE TABLE audit_table(col_new VARCHAR2(10),col_old VARCHAR2(10));
DECLARE
TYPE rec IS RECORD (actual A.columnA%TYPE, old A.columnA%TYPE);
TYPE col_a_t IS TABLE OF rec;
v_a col_a_t;
BEGIN
UPDATE (SELECT A.*, (SELECT A.columnA FROM dual) AS old_columnA FROM A)
SET columnA = 'XYZ'
WHERE columnB < 30
RETURNING columnA, old_columnA BULK COLLECT INTO v_a;
COMMIT;
-- printing for debug
FOR i IN v_a.first .. v_a.last LOOP
dbms_output.put_line('Old =>' || v_a(i).old || ' new => ' || v_a(i).actual);
END LOOP;
-- additional
FORALL i IN v_a.first .. v_a.last
INSERT INTO audit_table VALUES v_a(i);
COMMIT;
END;
/
SELECT * FROM A;
SELECT * FROM audit_table;
DBFiddle Demo
から取られたアイデア:Returning Old value during update