function makeHtml(response) {
$.each(response.workers,function(i){
$.each(response.dutchDays,function(j) {
var dayFrom = 'day'+j+'from';
console.log(response.workers[i].dayFrom); // This is showing me undefined
}
}
dutchDays:{1: "Maandag:", 2: "Dinsdag:", 3: "Woensdag:", 4: "Donderdag:", 5: "Vrijdag:", 6: "Zaterdag:",…}
timeArray:["00:00:00", "00:30:00", "01:00:00", "01:30:00", "02:00:00", "02:30:00", "03:00:00", "03:30:00",…]
workers:[{"workerid":"51","barberid":"41","name":"Mo","workerEmail":"[email protected]","worker_time_id":"57","time_needed":"30","day1from":"12:00:00","day1to":"18:00:00","day2from":"09:00:00","day2to":"18:00:00","day3from":"09:00:00","day3to":"18:00:00","day4from":"09:00:00","day4to":"20:30:00","day5from":"09:00:00","day5to":"18:00:00","day6from":"09:00:00","day6to":"18:00:00","day7from":"05:00:00","day7to":"12:30:00"}]
これは私が動的day1fromとday1to、day2fromとday2to ... jqueryの各ループ内のworker json配列から使いたいという私の関数です。私は未定義であることを示しています。jsonデータを取得中にjqueryに問題があります
それが働いている@Halcyon私はあなたが 'response.workers [i]が[dayFrom]' – Halcyon
たいと思いますありがとうございました:) –
を "ドット対ブラケット" を検索する理由の詳細について。 – Halcyon