PL/SQL数値または値のエラー：番号変換エラーに文字

Question

手順コード：

CREATE OR REPLACE PROCEDURE GetOrder(
p_Order IN NUMBER, 
p_OrderDate OUT DATE, 
p_CusNbr OUT NUMBER, 
p_OrderOut OUT NUMBER, 
p_Name OUT VARCHAR2, 
p_Address OUT VARCHAR2, 
p_City OUT VARCHAR2, 
p_State OUT CHAR, 
p_Zip OUT NUMBER, 
p_Itm OUT NUMBER, 
p_Desc OUT VARCHAR2, 
p_Qty OUT NUMBER, 
p_Price OUT NUMBER) 
AS 
v_OrderDate ord.ord_date%type; 
v_CusNbr ord.Cus_nbr%type; 
v_Order ord.Ord_nbr%type; 
v_Name cus.cus_nme%type; 
v_Address cus.str_adr%type; 
v_City zip.city%type; 
v_state zip.st%type; 
v_Zip zip.zip%type; 
v_Itm itm.itm_nbr%type; 
v_Desc itm.ITM_DSC%TYPE; 
v_Qty ord_itm.ord_Qty%type; 
v_Price itm.ord_itm_price%type; 
BEGIN 
SELECT O.ORD_NBR, C.CUS_NBR, O.ORD_DATE, C.CUS_NME, C.STR_ADR, Z.CITY, Z.ST, I.ITM_NBR, I.ITM_DSC, OI.ORD_QTY, I.ORD_ITM_PRICE 
     INTO 
     v_Order, v_CusNbr, v_OrderDate, v_Name, v_Address, v_Zip, v_state, v_Itm, v_Desc, v_Qty, v_Price 
FROM ITM I JOIN ORD_ITM OI ON (I.ITM_NBR = OI.ITM_NBR) 
      JOIN ORD O ON (OI.ORD_NBR = O.ORD_NBR) 
      JOIN CUS C ON (O.CUS_NBR = C.CUS_NBR) 
      JOIN ZIP Z ON (C.ZIP_ADR = Z.ZIP) 
WHERE O.ORD_NBR = p_Order; 
DBMS_OUTPUT.PUT_LINE('ILLINOIS COMPUTERS'); 
DBMS_OUTPUT.PUT_LINE('CUSTOMER ORDER FORM'); 
DBMS_OUTPUT.PUT_LINE(v_Order || v_OrderDate || v_CusNbr); 
DBMS_OUTPUT.PUT_LINE('Name: ' || v_Name); 
DBMS_OUTPUT.PUT_LINE('Address: ' || v_Address); 
DBMS_OUTPUT.PUT_LINE('City: ' || v_City || ' State : ' || v_state || ' Zip: ' || v_Zip); 
DBMS_OUTPUT.PUT_LINE('Item No.' || 'Description' || 'Quantity' || 'Price'); 
DBMS_OUTPUT.PUT_LINE(v_Itm || v_Desc || v_Qty || v_Price); 
END GetOrder; 
/

そして、私はプロシージャを呼び出す：

DECLARE 
    p_OrderNbr NUMBER := &ordernumber; 
    p_OrderDateOutput DATE; 
    p_CusNbrOutput  NUMBER; 
    p_OrderNbrOutput NUMBER; 
    p_NameOutput  cus.cus_nme%type; 
    p_AddressOutput  cus.str_adr%type; 
    p_CityOutput  zip.city%type; 
    p_StateOutput  CHAR; 
    p_ZipOutput   NUMBER; 
    p_ItmOutput   NUMBER; 
    p_DescOutput  itm.itm_dsc%type; 
    p_QtyOutput   NUMBER; 
    p_PriceOutput  NUMBER; 
begin 
    GetOrder(p_OrderNbr, 
    p_OrderDateOutput, 
    p_CusNbrOutput, 
    p_OrderNbrOutput, 
    p_NameOutput, 
    p_AddressOutput, 
    p_CityOutput, 
    p_StateOutput, 
    p_ZipOutput, 
    p_ItmOutput, 
    p_DescOutput, 
    p_QtyOutput, 
    p_PriceOutput); 
END; 
/

私は

ORA-06502 error: numeric or value error: character to number conversion error.

を取得しています

私はすべてのパラメータが順番に並んでいると思いますので、矛盾する変数の割り当てが得られていません。

このクエリを別々に実行して、適切な出力が得られていることを確認してください。正常に動作します。

SELECT O.ORD_NBR, C.CUS_NBR, O.ORD_DATE, C.CUS_NME, C.STR_ADR, Z.CITY, Z.ST, I.ITM_NBR, I.ITM_DSC, OI.ORD_QTY, I.ORD_ITM_PRICE 
     --INTO 
     --v_Order, v_CusNbr, v_OrderDate, v_Name, v_Address, v_Zip, v_state, v_Itm, v_Desc, v_Qty, v_Price 
FROM ITM I JOIN ORD_ITM OI ON (I.ITM_NBR = OI.ITM_NBR) 
      JOIN ORD O ON (OI.ORD_NBR = O.ORD_NBR) 
      JOIN CUS C ON (O.CUS_NBR = C.CUS_NBR) 
      JOIN ZIP Z ON (C.ZIP_ADR = Z.ZIP) 
WHERE O.ORD_NBR = 100; 

Answer 1

選択リストは、リストに

... C.STR_ADR, Z.CITY, Z.ST, ... 

を言う

... v_Address, v_Zip, v_state ... 

言うあなたはZテーブルに間違ったフィールドを得たようです。

Z.CITYが数値の郵便番号ですか？