HTTPプロキシを作成中にpython 3でsocket.makefileが発生する

Question

from socket import * 
import sys 

# Create a server socket, bind it to a port and start listening 
tcpSerSock = socket(AF_INET, SOCK_STREAM) 
serverPort = 12000 
tcpSerSock.bind(('', serverPort)) 
tcpSerSock.listen(1) 
print ("Server ready") 

while 1==1: 
    # Start receiving data from the client. e.g. request = "GET http://localhost:portNum/www.google.com" 
    tcpCliSock, addr = tcpSerSock.accept() 
    print ('Received a connection from:', addr) 
    request = str(tcpCliSock.recv(1024).decode()) 
    print ("Requested " + request) 
    # Extract the file name from the given request 
    fileName = request.split()[1] 
    print ("File name is " + fileName) 

    fileExist = "false" 
    fileToUse = "/" + fileName 

    print ("File to use: " + fileToUse) 
    try: 
    # Check wether the file exist in the cache. The open will fail and go to "except" in case the file doesn't exist. Similar to try/catch in java 
    f = open(fileToUse[1:], "r")      
    outputData = f.readlines()       
    fileExist = "true" 
    # ProxyServer finds a cache hit and generates a response message 
    tcpCliSock.send("HTTP/1.1 200 OK\r\n")    
    tcpCliSock.send("Content-Type:text/html\r\n") 
    tcpCliSock.send(outputData) 
    print ('This was read from cache')  

    except IOError: 
    if fileExist == "false": 
     # Create a socket on the proxyserver 
     c = socket(AF_INET, SOCK_STREAM) 
     hostn = fileName.replace("www.","",1) #max arg specified to 1 in case the webpage contains "www." other than the usual one   
     print (hostn)         
     try: 
      # Connect to the socket to port 80 
      c.bind(('', 80)) 
      # Create a temporary file on this socket and ask port 80 for the file requested by the client 
      print("premake") 

      fileObj = c.makefile('r', 0) 

      print("postmake") 
      fileObj.write("GET " + "http://" + fileName + " HTTP/1.1\r\n") 
      # Read the response into buffer 
      print("post write") 
      buff = fileObj.readlines() 
      # Create a new file in the cache for the requested file. 
      tmpFile = open("./" + filename,"wb") 
      # Send the response in the buffer to both client socket and the corresponding file in the cache 
      for line in buff: 
       tmpFile.write(line) 
      tcpCliSock.send(tmpFile) 

     except: 
      print ("Illegal request") 
      break            
    else: 
     # HTTP response message for file not found 
     print("HTTP response Not found") 

# Close the client and the server sockets  
tcpCliSock.close() 
#tcpSerSock.close() 

「IOErrorを除いて」入力された「try」を実行することは決してありません。問題はpython 3のための貧弱なドキュメントを持っているsocket.makefile（mode、buffsize）関数のようです。私は 'rwb'、 'r +'、 'r + b'などを関数に渡してみましたが、私はファイルを作成し、それ以降は書き込めません。

Answer 1

これはpython2.7とpython3の問題です。 makefile('r',0)はpython 2.7で動作しますが、python3ではmakefile('r',None)が必要です。 python2.7のドキュメントから

： socket.makefile([mode[, bufsize]])

のpython3のドキュメントから： socket.makefile(mode='r', buffering=None, *, encoding=None, errors=None, newline=None)