PHP：文字列内の任意の長さのシーケンスをすべて見つけるにはどうすればよいですか？

Question

私はユーザー入力（文字列）を取って、すべての可能な長さの単語の組み合わせ（配列）のリストに変換したいが、順番に並んでいる組み合わせだけを保持したい。

ので、下記のPHPに記載された配列は、最終的に次のようになり、次のように

$newArray = ["this","string","will","be","chopped","up","this string","will be","be chopped","chopped up","this string will","string will be","be chopped up"];

私のコード（動作しない）は次のとおりです。

PHP

$str = "This string will be chopped up."; 
$str = strtolower($str); 
$strSafe = preg_replace("/[^0-9a-z\s-_]/i","",$str); 
$array = explode(" ", $strSafe); 
$newArray = []; 
$newArrayEntry = []; 

for($counter=0; $counter < COUNT($oneword); $counter++) { 

    // List single words - as in array $oneword. 
    echo "One word: "; 
    echo $oneword[$counter]; 
    echo "<br />"; 

    $counterTwo = $counter+1;  

    if($counterTwo <= COUNT($oneword)) { 
     $newArrayEntry[COUNT($newArrayEntry)] = $oneword[$counter]; 
     print "Adding counter One to newArray Entry: ".$oneword[$counter]."<br />"; 
     for($counterThree=($counter+1); $counterThree < $counterTwo; $counterThree++) { 
      $newArrayEntry[COUNT($newArrayEntry)] = $oneword[$counterThree]; 

      if($counterThree - $counterTwo == 1) { 
       $newArrayEntry[COUNT($newArrayEntry)] = $oneword[$counterTwo]; 
       print "Adding counter Two to newArrayEntry: ".$oneword[$counterTwo]."<br />"; 
      } 
     } 
     $newArrayString = join(' ', $newArrayEntry); 
     $newArray[COUNT($newArray)] = $newArrayString; 
    } 
} 

Answer 1

ますこのコードを使用できます：

$str = "This string will be chopped up."; 
$str = strtolower($str); 
$strSafe = preg_replace("/[^0-9a-z\s-_]/i","",$str); 
$array = explode(" ", $strSafe); 
$newArray = []; 

for ($len = 1; $len <= count($array); $len++) { 
    for($start = 0; $start+$len <= count($array); $start++) { 
     $newArray[] = implode(" ", array_slice($array, $start, $len)); 
    } 
} 


var_export($newArray); 

出力：

array (
    0 => 'this', 
    1 => 'string', 
    2 => 'will', 
    3 => 'be', 
    4 => 'chopped', 
    5 => 'up', 
    6 => 'this string', 
    7 => 'string will', 
    8 => 'will be', 
    9 => 'be chopped', 
    10 => 'chopped up', 
    11 => 'this string will', 
    12 => 'string will be', 
    13 => 'will be chopped', 
    14 => 'be chopped up', 
    15 => 'this string will be', 
    16 => 'string will be chopped', 
    17 => 'will be chopped up', 
    18 => 'this string will be chopped', 
    19 => 'string will be chopped up', 
    20 => 'this string will be chopped up', 
)