2016-05-17 34 views
0

従業員のIDプロパティにTitleID値が設定されていることがわかりました(UPDATE 3のServiceStack - [Reference] or [Ignore]?参照)4.0.56の問題があります。ServiceStack DTOマッピングの問題

DTOはリクエスト:

[Route("/employees", "GET")] 
public class FindEmployeesRequest : QueryDb<Employee>, 
    IJoin<Employee, EmployeeType>, 
    IJoin<Employee, Department>, 
    IJoin<Employee, Title> { 

    public int? ID { get; set; } 
    public int[] IDs { get; set; } 
    public string UserID { get; set; } 
    public string[] UserIDs { get; set; } 
    public int? EmployeeTypeID { get; set; } 
    public int[] EmployeeTypeIDs { get; set; } 
    public int? DepartmentID { get; set; } 
    public int[] DepartmentIDs { get; set; } 
    public int? TitleID { get; set; } 
    public int[] TitleIDs { get; set; } 
    public string LastNameStartsWith { get; set; } 
    public DateTime[] DateOfBirthBetween { get; set; } 
    public DateTime[] HireDateBetween { get; set; } 
    public bool? IsActive { get; set; } 
    public bool? IsEligibleToOrderLunch { get; set; } 

    [QueryDbField(Template = "(MONTH({Field}) = {Value})", Field = "DateOfBirth")] 
    public int? BirthMonth { get; set; } 

    [QueryDbField(Template = "(DAY({Field}) = {Value})", Field = "DateOfBirth")] 
    public int? BirthDay { get; set; } 

    [QueryDbField(Template = "({Field} LIKE '%(Incoming)')", Field = "EmployeeTypeName")] 
    public bool? IsIncoming { get; set; } 

    [QueryDbField(Template = "(FirstName LIKE {Value} OR LastName LIKE {Value} OR PreferredName LIKE {Value})", ValueFormat = "%{0}%", Field = "ID")] 
    public string NameSearch { get; set; } 

    [QueryDbField(Template = "(FirstName LIKE {Value} OR LastName LIKE {Value} OR PreferredName LIKE {Value} OR Department.Name LIKE {Value} OR Title.Name LIKE {Value})", ValueFormat = "%{0}%", Field = "ID")] 
    public string BasicSearch { get; set; } 

    [QueryDbField(Template = "({Field} LIKE {Value})", Field = "EmployeeTypeName", ValueFormat = "%{0}%")] 
    public string EmployeeTypeSearch { get; set; } 

    [QueryDbField(Template = "({Field} LIKE {Value})", Field = "DepartmentName", ValueFormat = "%{0}%")] 
    public string DepartmentSearch { get; set; } 

    [QueryDbField(Template = "({Field} LIKE {Value})", Field = "TitleName", ValueFormat = "%{0}%")] 
    public string TitleSearch { get; set; } 
} 

問題を示す "SELECT * FROM" ん基本的にすべての要求 - ここのためのプロファイラからいくつかのSQLです: "/従業員がID = 101の&フィールド= *?"

:。(TitleID)

exec sp_executesql N'SELECT * 
FROM "Employee" INNER JOIN "EmployeeType" ON 
("EmployeeType"."ID" = "Employee"."EmployeeTypeID") INNER JOIN "Department" ON 
("Department"."ID" = "Employee"."DepartmentID") INNER JOIN "Title" ON 
("Title"."ID" = "Employee"."TitleID") 
WHERE "Employee"."ID" = @0',N'@0 int',@0=101 

私はこのクエリを自分自身を実行すると、 "従業員" "ID" は101ですが、サービスからの応答では、それは67です0

答えて

2

裸のワイルドカード?fields=*を単独で使用することはできません。テーブルプレフィックスを含める必要があります。 ?fields=employee.*としてmentioned in the docsと入力します。これは、テーブル内の各フィールドを手動で指定することを簡略化したものです。

+0

ありがとう@mythz - RTFM ... – jaybird

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