特定の文字列をテキストファイルで検索して分割し、保存した出力

Question

数字とアルファベットの文字を含む行で特定の文字列を分割する方法。私が持っている

設定データは、この（tembin-data.dat）のようなものです：

['3317121918', '69N1345E', '15'] 

['3317122000', '72N1337E', '20'] 

['3317122006', '75N1330E', '20'] 

['3317122012', '78N1321E', '20'] 

['3317122018', '83N1310E', '25'] 

.......etc 

私はちょうどこのよう"N"と"E"を除去することで、新たなデータ配置が必要になります。私が使用

['3317121918', '69','1345','15'] 

['3317122000', '72','1337','20'] 

['3317122006', '75','1330','20'] 

['3317122012', '78','1321','20'] 

['3317122018', '83','1310','25'] 

.......etc 

Pythonスクリプト瞬間は次のようになります：

newfile = open('tembin-data.dat', 'w') 
with open('tembin4.dat', 'r') as inF: 
    for line in inF: 
     myString = '331712' 
     if myString in line: 
      data=line.split() 
      print data 
      newfile.write("%s\n" % data) 
newfile.close() 

tembin4.datは次のとおりです。

REMARKS: 

230900Z POSITION NEAR 7.8N 118.6E. 

TROPICAL STORM 33W (TEMBIN), LOCATED APPROXIMATELY 769 NM EAST- 

SOUTHEAST OF HO CHI MINH CITY, VIETNAM, HAS TRACKED WESTWARD AT 

11 KNOTS OVER THE PAST SIX HOURS. MAXIMUM SIGNIFICANT WAVE HEIGHT 

AT 230600Z IS 14 FEET. NEXT WARNINGS AT 231500Z,0Z, 240300Z 

AND 240900Z.// 

3317121918 69N1345E 15 

3317122000 72N1337E 20 

3317122006 75N1330E 20 

3317122012 78N1321E 20 

3317122018 83N1310E 25 

3317122100 86N1295E 35 

3317122106 85N1284E 35 

3317122112 84N1276E 40 

3317122118 79N1267E 50 

3317122118 79N1267E 50 

3317122200 78N1256E 45 

3317122206 78N1236E 45 

3317122212 80N1225E 45 

3317122218 79N1214E 50 

3317122218 79N1214E 50 

3317122300 77N1204E 55 

3317122300 77N1204E 55 

3317122306 77N1193E 55 

3317122306 77N1193E 55 

NNNN 

Answer 1

あなたはのpython3にこの短いソリューションを試すことができます。

import re 
s = [['3317121918', '69N1345E', '15'], ['3317122000', '72N1337E', '20'], ['3317122006', '75N1330E', '20'], ['3317122012', '78N1321E', '20'], 
['3317122018', '83N1310E', '25']] 
new_s = [[a, *re.findall('\d+', b), c] for a, b, c in s] 

出力：

[['3317121918', '69', '1345', '15'], ['3317122000', '72', '1337', '20'], ['3317122006', '75', '1330', '20'], ['3317122012', '78', '1321', '20'], ['3317122018', '83', '1310', '25']] 

Answer 2

パンダを使用すると簡単にこれを行うことができます。

import pandas as pd 
import os # optional 

os.chdir('C:\\Users') # optional 
df = pd.read_csv('tembin-data.dat', header = None) 

df[3]= df[1].str.slice(1,3) 
df[4]= df[1].str.slice(4,8) 

df = df.drop(1, axis = 1) 

df.to_csv('tembin-out.dat',header=False) 

Answer 3

このお試しください：ただ正規表現と分割して、あなたのアプローチを拡張

import re 
for line in open(r"tembin4.txt","r"): 
    lst = line.split(" ") 
    for i,x in enumerate(lst): 
     grp = re.findall('(\d+)N(\d+)E',x) 
     if len(grp) !=0: 
      lst.remove(x) 
      lst.insert(i,grp[0][1]) 
      lst.insert(i,grp[0][0]) 
    print(" ".join(lst)) 

Answer 4

を。あなたがPositive Lookbehind (?<=N)とPositive Lookahead(?=N)を使用して、ちょうどグループをキャプチャすることができ

import re 
newfile = open('tembin-data.dat', 'w') 

pat = re.compile("[N|E]") 

with open('tembin4.dat', 'r') as inF: 
for line in inF: 
    myString = '331712' 
    if myString in line: 
     data=line.split() 
     data[2:2] = pat.split(data[1])[:-1] # insert the list flattend at index 2 
     del data[1] # Remove string with N&E from list. 
     print data 
     newfile.write("%s\n" % data) 

Answer 5

：

import re 
pattern="'\d+'|(\d+)(?=N)|(?<=N)(\d+)" 
with open('file.txt','r') as f: 
    for line in f: 
     sub_list=[] 
     search=re.finditer(pattern,line) 
     for lin in search: 
      sub_list.append(int(lin.group().strip("'"))) 

     if sub_list: 
      print(sub_list) 

出力：

[3317121918, 69, 1345, 15] 
[3317122000, 72, 1337, 20] 
[3317122006, 75, 1330, 20] 
[3317122012, 78, 1321, 20] 
[3317122018, 83, 1310, 25] 

正規表現情報：

'\d+'|(\d+)(?=N)|(?<=N)(\d+)/g' 

\d+ matches a digit (equal to [0-9]) 
+ Quantifier — Matches between one and unlimited times, as many times as possible, giving back as needed 

Positive Lookahead (?=N) 
Assert that the Regex below matches 
N matches the character N literally (case sensitive) 

Positive Lookbehind (?<=N) 
Assert that the Regex below matches 
N matches the character N literally (case sensitive)