If-Else Statementが正しく実行されていません

Question

これは私のコードですが、私は無料修正を求めていません。私は助けてくれる人を探しています。前もって感謝します！

* Psuedocode: 
* 1. Ask the user if they want to enter a number or if they want the computer to select a random number. 
* 2. Based on the user selection, Ask the user for a number or generate a random number. 
* 3. Read the number from the user (Skip the step if a random number is generated) 
* 4. Check if the number is 1 digit or 2 digit or 3 digit or 4 digit 
* 5. if it is 1 digit then check if the cube of number equals the number 
* 6. else if it is 2 digit, get the cube of first and second digits and then sum them up and check if the number is equal to the sum. 
* 7. else if it is 3 digit, get the cube of first, second and third digits and then sum them up andcheck if the number is equal to the sum. 
* 8. if it is 4 digit, get the cube of first, second, third and fourth digits and then sum them up andcheck if the number is equal to the sum. 
* 9. else tell the user that the number they have entered is not within 9999 
* 10. Print a closing message saying if the number is an Armstrong number or not. 
* 11. Print a goodbye statement. 

*/

import java.util.Scanner; 
    import java.util.Random; 

    public class ArmstrongNumber { 

     public static boolean Armstrong(int input) { 
      String inputString = input + ""; 
     int numberOfDigits = inputString.length(); 
     int copyOfInput = input; 
     int sum = 0; 

     while (copyOfInput != 0) { 
      int lastDigit = copyOfInput % 10; 
      sum = sum + (int) Math.pow(lastDigit, numberOfDigits); 
      copyOfInput = copyOfInput/10; 
     } 
     if (sum == input) { 
      return true; 
     } else { 
      return false; 
     } 
    } 

     public static void main(String[] args) { 
      Scanner scanner = new Scanner(System.in); 

      System.out.print("Enter a number to check if it is an Armstrong number or generate a random number: "); 
     int inputNumber = scanner.nextInt(); 
     int choice = 0; 
     Random rand = new Random(); 
     if(choice == 1) 
     { 
        inputNumber = scanner.nextInt(); 
     } 
     else if(choice == 2) 
     { 
        inputNumber = rand.nextInt(9999) + 1; ;//generate a random number between 1 and 9999 
     } 





     boolean result = Armstrong(inputNumber); 
     if (result) { 
      System.out.println(""); 
      System.out.println(inputNumber + " is an Armstrong number"); 
     } else { 
      System.out.println(""); 
      System.out.println(inputNumber + " is not an Armstrong number"); 

     } 
     System.out.println(""); 
     System.out.println("Thanks for using my code. Goodbye"); 
    } 
} 

私の選択肢のための乱数発生方法が機能していません。このコードで選択2

Answer 1

ための乱数を発生させるアームストロング番号やないアームストロングの番号ではなく、どちらかが

int choice = 0; 
    Random rand = new Random(); 
    // you need to assign something to choice before the next line 
    // maybe choice = rand.nextInt(); ? 
    if(choice == 1)