CakePHPの3.xのサブ選択

Question

後の私は、この検索文を作成し、それが期待通りに動作しないいくつかの研究：

public $virtualFields = array(
    'count' => "SELECT COUNT(plans_trainings.id) FROM plans_trainings, trainings, projects WHERE plans_trainings.training_id = trainings.id AND projects.location_id = locations.id AND plans_trainings.project_id = projects.id" 
); 

public function trainingsPerLocationChartData(){ 
$this->loadModel('Locations'); 
$locationsDiagramData = $this->Locations->find('all', array(
      'fields' => array(
       'locations.id', 
       'locations.description', 
       'locations.count' /* virtuel field */ 
      ) 
     )); 

文は次のようになります。

'sql' => 'SELECT locations.id AS `locations__id`, locations.description AS `locations__description`, locations.count AS `locations__count` FROM locations Locations' 

仮想フィールドがまったく認識されません。 どうすれば間違っていますか？

UPDATE： 私はこのようにそれを呼び出す必要があることが分かった：

'count' => "(SELECT COUNT(plans_trainings.id) FROM plans_trainings, trainings, projects WHERE plans_trainings.training_id = trainings.id AND projects.location_id = locations.id AND plans_trainings.project_id = projects.id) AS `counter`" 

私は選択の周り）（追加しました。

$locationsDiagramData = $this->Locations->find('all') 
      ->select(['locations.id', 'locations.description', $this->virtualFields['count']]); 

しかし、私はまだ間違ったSQL構文を取得：

SELECT locations.id AS `locations__id`, locations.description AS `locations__description`, (SELECT COUNT(plans_trainings.id) FROM plans_trainings, trainings, projects WHERE plans_trainings.training_id = trainings.id AND projects.location_id = locations.id AND plans_trainings.project_id = projects.id) AS `counter` AS (SELECT COUNT(plans_trainings__id) FROM plans_trainings, trainings, projects WHERE plans_trainings FROM locations Locations 

"最後" の問題は、AS counter後にのみ、この部分に思える：

AS（SELECT COUNT（plans_trainings__id）FROM plans_trainings、training、 プロジェクト計画通りの場所

これは、ステートメントが壊れたものです！ これを解決する方法はありますか？ phpmyadminでステートメントを実行し、この部分を削除した場合、ステートメントは正常に動作し、正しい結果が得られます！

UPDATE 2： これは平野文です：

select 
       locations.id, 
    locations.description, 
    (
           select 
               count(plans_trainings.id) 
           from 
               plans_trainings, 
      trainings, 
      projects 
           where 
               plans_trainings.training_id = trainings.id 
               and projects.location_id = locations.id 
               and plans_trainings.project_id = projects.id 
    ) as 'Anzahl' 
from 
       locations; 

Answer 1

適切な[**サブクエリを使用する... CakePHPの3には仮想フィールドはもうありませんコントローラ

$this->loadModel('Locations'); 
$this->loadModel('PlansTrainings'); 
$this->loadModel('Trainings'); 
$this->loadModel('Projects'); 
$sub_query=$this->PlansTrainings->find()->select(['cnt1'=>'count(PlansTrainings.id)'])->join([ 
     [ 
      'table' => 'trainings', 
      'alias' => 'Trainings', 
      'type' => 'INNER', 
      'conditions' => 'PlansTrainings.training_id=Trainings.id', 
     ], 
     [ 
      'table' => 'projects', 
      'alias' => 'Projects', 
      'type' => 'INNER', //LEFT, RIGHT... 
      'conditions' => ['Projects.location_id=PlansTrainings.id','PlansTrainings.project_id=Projects.id'], 
     ], 
]); 
$locationsDiagramData = $this->Locations->find()->select(['id', 'description','count'=>$sub_query]);