電卓 - 電源ボタン

Question

私はtkinterを使って電卓をコード化しようとしていましたが、これまでの4つの基本的な操作、加算、減算、乗算、除算をすべて作成しました。私はまた、すべての数字のための明確なボタンとボタンを作った。今私は "パワー"ボタンを作りたいと思います。私が電卓に入れたら答えは正解ではありません。誰かが電源ボタンを動作させる方法を知っていますが、そうすると他のボタンには影響しませんか？

コードはそこにあるので、私が何をしているのか分かります。

#calculator with tkinter 
import sys 
from tkinter import * 
from tkinter import messagebox 
from tkinter import filedialog 

a = Tk() 

frame = Frame(a) 
frame.pack() 

a.title('Calculator') 

def clear(): 
    mbox = textDisplay.delete(len(textDisplay.get())-1, END) 
    return 
def set_text(text): 
    textDisplay.insert(END, text) 
    return 

def clear_all(): 
    textDisplay.delete(0, END) 
    return 

def equals(): 
    try: 
     result = eval(textDisplay.get()) 
    except: 
     messagebox.showerror(message = 'Invalid Answer') 
    clear_all() 
    set_text(result) 





box = StringVar() 

topframe = Frame(a) 
topframe.pack(side = TOP) 

textDisplay = Entry(frame, textvariable = box, bd = 20, insertwidth = 1, font = 30) 
textDisplay.pack(side = TOP) 

button1 = Button(topframe, padx = 16, pady = 16, bd = 8, text = '1', command = lambda:set_text('1')) 
button1.pack(side = LEFT) 

button2 = Button(topframe, padx = 16, pady = 16, bd = 8, text = '2', command = lambda:set_text('2')) 
button2.pack(side = LEFT) 

button3 = Button(topframe, padx = 16, pady = 16, bd = 8, text = '3', command = lambda:set_text('3')) 
button3.pack(side = LEFT) 

plus = Button(topframe, padx = 16, pady = 16, bd = 8, text = '+', command = lambda:set_text('+')) 
plus.pack(side = LEFT) 

middleframe = Frame(a) 
middleframe.pack(side = TOP) 

button4 = Button(middleframe, padx = 16, pady = 16, bd = 8, text = '4', command = lambda:set_text('4')) 
button4.pack(side = LEFT) 

button5 = Button(middleframe, padx = 16, pady = 16, bd = 8, text = '5', command = lambda:set_text('5')) 
button5.pack(side = LEFT) 

button6 = Button(middleframe, padx = 16, pady = 16, bd = 8, text = '6', command = lambda:set_text('6')) 
button6.pack(side = LEFT) 

minus = Button(middleframe, padx = 16, pady = 16, bd = 8, text = '-', command = lambda:set_text('-')) 
minus.pack(side = LEFT) 

bottomframe = Frame(a) 
bottomframe.pack(side = TOP) 

button7 = Button(bottomframe, padx = 16, pady = 16, bd = 8, text = '7', command = lambda:set_text('7')) 
button7.pack(side = LEFT) 

button8 = Button(bottomframe, padx = 16, pady = 16, bd = 8, text = '8', command = lambda:set_text('8')) 
button8.pack(side = LEFT) 

button9 = Button(bottomframe, padx = 16, pady = 16, bd = 8, text = '9', command = lambda:set_text('9')) 
button9.pack(side = LEFT) 

times = Button(bottomframe, padx = 16, pady = 16, bd = 8, text = 'x', command = lambda:set_text('*')) 
times.pack(side = LEFT) 

morebottom = Frame(a) 
morebottom.pack(side = TOP) 

equals = Button(morebottom, padx = 16, pady = 16, bd = 8, text = '=', command = equals) 
equals.pack(side = LEFT) 

button0 = Button(morebottom, padx = 16, pady = 16, bd = 8, text = '0', command = lambda:set_text('0')) 
button0.pack(side = LEFT) 

clearbu = Button(morebottom, padx = 16, pady = 16, bd = 8, text = 'C', command = clear) 
clearbu.pack(side = LEFT) 

div = Button(morebottom, padx = 16, pady = 16, bd = 8, text = '/', command = lambda:set_text('/')) 
div.pack(side = LEFT) 

evenmore = Frame(a) 
evenmore.pack(side = TOP) 

cebut = Button(evenmore, padx = 16, pady = 16, bd = 8, text = 'CE', command = clear_all) 
cebut.pack(side = LEFT) 

decimal = Button(evenmore, padx = 16, pady = 16, bd = 8, text = '.', command = lambda:set_text('.')) 
decimal.pack(side = LEFT) 

power = Button(evenmore, padx = 16, pady = 16, bd = 8, text = '^', command = lambda:set_text('^')) 
power.pack(side = LEFT) 

a.mainloop 

Answer 1

^ Pythonでパワーに数を上げる代わりに**を使用し、XORです。

^を**に変更してpower = Button(evenmore, padx = 16, pady = 16, bd = 8, text = '^', command = lambda:set_text('^'))を入力すると正しい結果が得られますが、電卓のディスプレイに**と表示されます。代わりにresult = eval(textDisplay.get())をresult = eval(textDisplay.get().replace('^', '**'))に置き換えて、期待されるシンボルが表示されるようにすることができますが、答えは正しいでしょう。