SQL分割タブ区切り列

Question

DBにタブ区切りの列があり、これにはヘッダーフィールドと関連する結果が含まれています。私はIP列に基づいて別々の行にそのデータを返すクエリの支援が必要です。以下は、データのサンプルと望ましい結果です。

以下のクエリでこの結果が得られます。

DECLARE @Tmp TABLE (ID int Identity(1,1), IP nvarchar(255),Results NVARCHAR(max)); 
INSERT into @Tmp select top 1 ip, Results from MyTable where results like 'Package%' 
select * from @Tmp 

これは望ましい結果です。

IP    Package  Installed Version   Required Version 
10.48.8.28  nss   3.21.0-9.el7_2.x86_64  3.21.3-2.el7_3 
10.48.8.28  nss-sysinit 3.21.0-9.el7_2.x86_64  3.21.3-2.el7_3 
10.48.8.28  nss-tools 3.21.0-9.el7_2.x86_64  3.21.3-2.el7_3 
10.48.8.28  nss-util  3.21.0-2.2.el7_2.x86_64 3.21.3-1.1.el7_3 

これは、SQL結果ウィンドウからクリップボードにコピーされたデータです。

ID IP   Results 
1 10.46.8.28 Package Installed Version Required Version 
       python 2.7.5-39.el7_2.x86_64 2.7.5-48.el7 
       python-libs 2.7.5-39.el7_2.x86_64 2.7.5-48.el7 

Answer 1

作成サンプルデータ（解析機能付き）この

オプション1のように見えます

Declare @YourTable table (ID int,IP varchar(50),TabString varchar(max)) 
Insert Into @YourTable values 
(1,'444.333.222.11','Package Installed Version Required Version 
nss 3.21.0-9.el7_2.x86_64 3.21.3-2.el7_3 
nss-sysinit 3.21.0-9.el7_2.x86_64 3.21.3-2.el7_3 
nss-tools 3.21.0-9.el7_2.x86_64 3.21.3-2.el7_3 
nss-util 3.21.0-2.2.el7_2.x86_64 3.21.3-1.1.el7_3') 

Select A.ID 
     ,A.IP 
     ,Package    = Pos1 
     ,[Installed Version] = Pos2 
     ,[Required Version] = Pos3 
From @YourTable A 
Cross Apply [dbo].[udf-Str-Parse](A.TabString,char(13)) B 
Cross Apply [dbo].[udf-Str-Parse-Row](B.RetVal,char(9)) C 
Where B.RetVal is not null and B.RetSeq>1 

の

戻り

（解析機能なし）オプション2

Select A.ID 
     ,A.IP 
     ,Package    = Pos1 
     ,[Installed Version] = Pos2 
     ,[Required Version] = Pos3 
From @YourTable A 
Cross Apply ( 
       Select RetSeq = Row_Number() over (Order By (Select null)) 
         ,RetVal = LTrim(RTrim(B.i.value('(./text())[1]', 'varchar(max)'))) 
       From (Select x = Cast('<x>' + replace((Select replace(A.TabString,char(13),'§§Split§§') as [*] For XML Path('')),'§§Split§§','</x><x>')+'</x>' as xml).query('.')) as X 
       Cross Apply x.nodes('x') AS B(i) 
      ) B 
Cross Apply (
       Select Pos1 = ltrim(rtrim(xDim.value('/x[1]','varchar(max)'))) 
         ,Pos2 = ltrim(rtrim(xDim.value('/x[2]','varchar(max)'))) 
         ,Pos3 = ltrim(rtrim(xDim.value('/x[3]','varchar(max)'))) 
         ,Pos4 = ltrim(rtrim(xDim.value('/x[4]','varchar(max)'))) 
       From (Select Cast('<x>' + replace((Select replace(B.RetVal,char(9),'§§Split§§') as [*] For XML Path('')),'§§Split§§','</x><x>')+'</x>' as xml) as xDim) as X 
      ) C 
Where B.RetVal is not null and B.RetSeq>1 

戻り

の

解析機能興味

CREATE FUNCTION [dbo].[udf-Str-Parse] (@String varchar(max),@Delimiter varchar(10)) 
Returns Table 
As 
Return ( 
    Select RetSeq = Row_Number() over (Order By (Select null)) 
      ,RetVal = LTrim(RTrim(B.i.value('(./text())[1]', 'varchar(max)'))) 
    From (Select x = Cast('<x>' + replace((Select replace(@String,@Delimiter,'§§Split§§') as [*] For XML Path('')),'§§Split§§','</x><x>')+'</x>' as xml).query('.')) as A 
    Cross Apply x.nodes('x') AS B(i) 
); 
--Thanks Shnugo for making this XML safe 
--Select * from [dbo].[udf-Str-Parse]('Dog,Cat,House,Car',',') 
--Select * from [dbo].[udf-Str-Parse]('John Cappelletti was here',' ') 
--Select * from [dbo].[udf-Str-Parse]('this,is,<test>,for,< & >',',') 

---

CREATE FUNCTION [dbo].[udf-Str-Parse-Row] (@String varchar(max),@Delimiter varchar(10)) 
Returns Table 
As 
Return (
    Select Pos1 = ltrim(rtrim(xDim.value('/x[1]','varchar(max)'))) 
      ,Pos2 = ltrim(rtrim(xDim.value('/x[2]','varchar(max)'))) 
      ,Pos3 = ltrim(rtrim(xDim.value('/x[3]','varchar(max)'))) 
      ,Pos4 = ltrim(rtrim(xDim.value('/x[4]','varchar(max)'))) 
      ,Pos5 = ltrim(rtrim(xDim.value('/x[5]','varchar(max)'))) 
      ,Pos6 = ltrim(rtrim(xDim.value('/x[6]','varchar(max)'))) 
      ,Pos7 = ltrim(rtrim(xDim.value('/x[7]','varchar(max)'))) 
      ,Pos8 = ltrim(rtrim(xDim.value('/x[8]','varchar(max)'))) 
      ,Pos9 = ltrim(rtrim(xDim.value('/x[9]','varchar(max)'))) 
    From (Select Cast('<x>' + replace((Select replace(@String,@Delimiter,'§§Split§§') as [*] For XML Path('')),'§§Split§§','</x><x>')+'</x>' as xml) as xDim) as A 
) 
--Thanks Shnugo for making this XML safe 
--Select * from [dbo].[udf-Str-Parse-Row]('Dog,Cat,House,Car',',') 
--Select * from [dbo].[udf-Str-Parse-Row]('John <test> Cappelletti',' ') 
--Select * from [dbo].[udf-Str-Parse-Row]('A&B;C;D;E, F;<x>',';') 

Answer 2

場合は、SQL Server 2016を使用している場合、あなたはそれが最速の方法ですアーロン・ベルトランによるとSTRING_SPLIT()

を使用することができます。これを参照してくださいhttps://sqlperformance.com/2016/03/sql-server-2016/string-split

Declare @YourTable table (ID int,IP varchar(50),TabString varchar(max)); 
Insert Into @YourTable values 
(1,'444.333.222.11','Package Installed Version Required Version 
nss 3.21.0-9.el7_2.x86_64 3.21.3-2.el7_3 
nss-sysinit 3.21.0-9.el7_2.x86_64 3.21.3-2.el7_3 
nss-tools 3.21.0-9.el7_2.x86_64 3.21.3-2.el7_3 
nss-util 3.21.0-2.2.el7_2.x86_64 3.21.3-1.1.el7_3'); 


;WITH CTE_Lines AS 
(
select ID, IP, a.ROWID , a.Lines from @YourTable 
    CROSS APPLY (
     SELECT 
      ROW_NUMBER() OVER (ORDER BY (SELECT 1)) AS ROWID, value Lines 
     FROM STRING_SPLIT(TabString, CHAR(13)) --Splits by new lines 
    ) a 
), CTE_Columns AS 
(
SELECT ID, IP, ROWID, b.ColsID, b.[Cols] FROM CTE_Lines 
    CROSS APPLY (
    SELECT 
     ROW_NUMBER() OVER (ORDER BY (SELECT 1)) AS ColsID, 
     value [Cols] 
     FROM STRING_SPLIT(Lines, CHAR(9)) --Splits by tabs 
    ) b 
    WHERE ROWID <> 1 --Removes the headers 
) 

SELECT ID, IP, [1] Package, [2] [Installed Version],[3] [Required Version] FROM 
(
    SELECT ID, IP, ROWID, ColsID, [Cols] FROM CTE_Columns 
) a 
PIVOT (MAX(a.Cols) FOR ColsId in ([1],[2],[3])) as pvt