私のサーバーにWebhookからJSON POSTデータが届きました。次のように私は、JSONデータを取得することができます。このJSONを返すPHP JSON値を取得する問題
$orderJSON = file_get_contents('php://input');
:
{
"order": {
"billing_address": {
"address_1": "76 Pacific Drive",
"address_2": "",
"city": "Bondi",
"company": "Hanson Media",
"country": "AU",
"email": "[email protected]",
"first_name": "Hansel",
"last_name": "Gretten",
"phone": "212 554 7855",
"postcode": "2026",
"state": "NSW"
},
"cart_tax": "3.60",
"completed_at": "2016-12-19T11:07:15Z",
"coupon_lines": [],
"created_at": "2016-12-19T11:07:15Z",
"currency": "AUD",
"customer": {
"billing_address": {
"address_1": "76 Pacific Drive",
"address_2": "",
"city": "Bondi",
"company": "Hanson Media",
"country": "AU",
"email": "[email protected]",
"first_name": "Hansel",
"last_name": "Gretten",
"phone": "212 554 7855",
"postcode": "2026",
"state": "NSW"
},
"email": "[email protected]",
"first_name": "Hansel",
"id": 0,
"last_name": "Gretten",
"shipping_address": {
"address_1": "76 Pacific Drive",
"address_2": "",
"city": "Bondi",
"company": "Hanson Media",
"country": "AU",
"first_name": "Hansel",
"last_name": "Gretten",
"postcode": "2026",
"state": "NSW"
}
},
"fee_lines": [],
"id": 3304,
"is_vat_exempt": false,
"line_items": [
{
"id": 113,
"meta": [],
"name": "Happy Ninja",
"price": "18.00",
"product_id": 37,
"quantity": 2,
"sku": "",
"subtotal": "36.00",
"subtotal_tax": "3.60",
"tax_class": null,
"total": "36.00",
"total_tax": "3.60"
},
{
"id": 114,
"meta": [],
"name": "Water Bottles",
"price": "20.50",
"product_id": 3291,
"quantity": 1,
"sku": "PD885536",
"subtotal": "20.50",
"subtotal_tax": "0.00",
"tax_class": "standard",
"total": "20.50",
"total_tax": "0.00"
}
],
"note": "Call to arrange delivery time",
"order_key": "wc_order_5857bf639d951",
"order_number": 3304,
"payment_details": {
"method_id": "eway",
"method_title": "Credit Card",
"paid": false
},
"shipping_address": {
"address_1": "76 Pacific Drive",
"address_2": "",
"city": "Bondi",
"company": "Hanson Media",
"country": "AU",
"first_name": "Hansel",
"last_name": "Gretten",
"postcode": "2026",
"state": "NSW"
},
"shipping_lines": [
{
"id": 115,
"method_id": "local_pickup:1",
"method_title": "Local Pickup",
"total": "0.00"
}
],
"shipping_methods": "Local Pickup",
"shipping_tax": "0.00",
"status": "pending",
"subtotal": "56.50",
"tax_lines": [
{
"code": "AU-GST-1",
"compound": false,
"id": 116,
"rate_id": "1",
"title": "GST",
"total": "3.60"
}
],
"total": "60.10",
"total_discount": "0.00",
"total_line_items_quantity": 3,
"total_shipping": "0.00",
"total_tax": "3.60",
"updated_at": "2016-12-19T11:07:15Z",
"view_order_url": "https://mywebsite.com/my-account/view-order/3304"
}
}
私は今、例えば、JSONから個々の要素を取得する必要があります私はid値(3304)を取得したいと思います。
$orderID = $orderJSON->id;
と
$orderID = $orderJSON[id];
をが、これは単に「非オブジェクトのプロパティを取得しようとすると」のようなエラーを生成します。私が試してみました。
引数が不正な場合、 'json_decode'は' null'を返します。 '$ orderJSON'が空でないかどうかをチェックすることが賢明です。それ以外の場合は、 '非オブジェクトのプロパティを取得しようとしています'と同じです。 –
@AlexBlexありがとうございます。私は自分の答えを更新しました – Hassaan
申し訳ありませんが、それは別の方法です。実際には変数名の再利用がベストプラクティスではないという良い例です。あなたの答えを編集してもらえませんか? –